Ask question

Ask question

All categories

goldfiish [28.3K]

4 years ago

8

An object is thrown upward from the top of a 48-foot building with an initial velocity of 32 feet per second. The height h of th

e object after t seconds is given by the quadratic equation h=-16t^2+33t+48. When will the object hit the ground?

1 answer:

Mars2501 [29]4 years ago

6 0

At 500^4 feet thanks

You might be interested in

88 times 7.3 eaquals

Elza [17]

Multiply 88 by 7, then multiply 88 by 3 and move the decimal point one to the left. Then add those two numbers. That's your answer.

5 0

3 years ago

Pls helppppp with my math

kow [346]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help me I'm on a time crunch

Neporo4naja [7]

You multiple it by 20....
1:20
2:40
3:60
4:80
5:100
So it’s 80 inches by 100 inches (80x100) =800 square feet

8 0

3 years ago

Read 2 more answers

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

3 years ago

A Farmer plants the same amount everyday, adding up to 1 3/4 acres at the end of the year. If the year is 1/2 over how many acre

DochEvi [55]

Answer:

1/45 acres the farmer planted

8 0

3 years ago