Answer:

Step-by-step explanation:




but if

then since


so

or





Answer:Dog's weight> 80 pounds
Step-by-step explanation:Dog's weight is greater than 80 pounds
Let c= cost to rent each other
Let t= cost to rent each other
2c+3t=25
6T+5T=49
Multiply the 2nd equation by (-2) and add equation together
2c+3t=25
-12c-10t= 98
2t=98
T=49
Put this value into the 1st equation solve c
2c+3(49)=49
2c+147=49
2c=98
C=49
Cost to each chair and table are same 49.
Answer:
294
Step-by-step explanation:
100%-> 700
42%->294
The answer is 5.5 m.
Cube
Volume = length x width x height
Since the length, width and the height are the same in cube, the formula can be:
Volume = length^3
Let x metres be the side length of the cube.
166 = x^3
x = ∛166
x = 5.495864.....
x = 5.5 (nearest tenth)