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natali 33 [55]
3 years ago
15

What are the four basic functions of amedern computer?​

Physics
1 answer:
Snezhnost [94]3 years ago
7 0

Answer

input, output, processing and storage

Explanation:

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The terminals of a 0.70 Vwatch battery are connected by a 80.0-m-long gold wire with a diameter of 0.200 mm What is the current
Komok [63]

Answer:

I=0.047A

Explanation:

Let's use Ohm's law:

V=IR  

or

I=\frac{V}{R}   (1)

Where:

V=Voltage\\I=Current\\R=Electrical\hspace{2 mm}Resistance

We know the value of the voltage V, so we need to find the value of R in order to find I. Fortunately there is a relation between the resistivity of a conductor and its electrical resistance given by:

R=\rho*\frac{l}{A}    (2)

Where:

R=Electrical\hspace{2 mm}Resistance\\l=Length\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=80m\\A=Cross\hspace{2 mm}sectional\hspace{2 mm}area\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=1.256637061*10^{-7} \\\rho=Electrical\hspace{2 mm}resistivity\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}material=2.35*10^{-8}

Keep in mind that the electrical resistivity of the gold is a known constant which is \rho_g_o_l_d=2.35*10^{-8} and the cross sectional area of the conductor is calculated as:

A=\pi *(r^{2})=\pi  *(0.0002m)^{2} =1.256637061*10^{-7} m^{2}

Because we have a wire in this case, so we assume a cylindrical geometry.

Now replacing our data in (2)

R=(2.35*10^{-8})*\frac{80}{1.256637061*10^{-7} }  =14.96056465\Omega

Finally, we know R and V, so replacing these values in (1) we will be able to find the current:

I=\frac{0.7}{14.96056465}\approx0.047A

7 0
3 years ago
A stone has a volume of 0.50 cm³ and a mass of
Dafna1 [17]

Answer:

ρ = M / V = 2 g / .5 cm^3 = 4 g/cm^3

8 0
2 years ago
Cold air masses tend to originate from: Question 3 options: tropical areas an area where it's wintertime an area where it's summ
suter [353]

Answer:

Polar areas

Explanation:

From what I know Arctic, Antarctic, and polar air masses are cold.  Polar (cold), Arctic (very cold), Equatorial (warm and very moist), and Tropical (warm).

  • With the options you gave, you can immeditaly elimate 1. tropical areas and 2. an area where its summertime.
  • Your then left with two options 1. an area where its wintertime and 2. polar areas

I then concluded that cold air masses tend to originate from POLAR AREAS.

6 0
2 years ago
Read 2 more answers
We now slowly increase the pressure to 15464.04 Pa while keeping the temperature constant. What is the final volume?
Mila [183]

Answer:

Final volume = 0.42 cubic meters

Explanation:

The question is incomplete. The initial conditions are

Initial temperature ,T_{1} = 310 K

Initial volume ,V_{1} = 0.5 cubic meter

Number of moles = 2.5

Since, from the ideal gas equation we get,

PV = nRT

P \times 0.5 = 2.5 \times 8.314 \times 310

P_{1} = 12886.7 Pa

Final pressure= 15464.04 Pa

Since temperature is constant,

PV = constant

12886.7 \times 0.5 = 15464.04 \times V

V = 0.42 cubic meters.

Hence final volume = 0.42 cubic meters

8 0
3 years ago
Which of the following is the correct unit for time when calculating power in watts?
aleksklad [387]
<span>Which of the following is the correct unit for time when calculating power in watts?
</span>
The correct unit for time when calculating power in watts is seconds. The answer is letter D. The rest of the choices do not answer the question above.
7 0
3 years ago
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