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OverLord2011 [107]

4 years ago

8

The velocity of waves in a ripple tank is 20 centimeters per second, and standing waves are produced with nodes spaced 3.0 centi

meters apart. what is the frequency of the wave generator?

1 answer:

Firlakuza [10]4 years ago

6 0

Velocity = wavelength x frequency
20=3f
f=20/3
f=6.667hz

You might be interested in

Consider a pendulum of length 3. 171 m. The acceleration of gravity is 9. 832 m/s2. A) what is its period at the north pole?answ

ch4aika [34]

The period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.

<h3>What is time period of pendulum?</h3>

Pendulum is the body which is pivoted to a point and perform back and forth motion around that point by swinging due to the influence of gravity.

The time period of a pendulum is the time taken by it to complete one cycle of swing left to right and right to left.

It can be given as,

$T=2\pi \sqrt{\dfrac{L}{g}}$

Here, (g) is the gravitational force of Earth and (L) is the length of the pendulum.

A pendulum of length 3.171 m. The acceleration of gravity is 9.832 m/s2. The period at the north pole is,

$T=2\pi \sqrt{\dfrac{3.171}{9.832}}\\T=3.57\rm\; s$

Thus, the period of the pendulum of length 3. 171 m when acceleration of gravity is 9. 832 m/s, is 3.57 seconds.

Learn more about the time period of pendulum here;

brainly.com/question/3551146

#SPJ4

4 0

2 years ago

Two identical horizontal sheets of glass have a thin film of air of thickness t between them. The glass has refractive index 1.4

Gre4nikov [31]

Answer:

the wavelength λ of the light when it is traveling in air = 560 nm

the smallest thickness t of the air film = 140 nm

Explanation:

From the question; the path difference is Δx = 2t (since the condition of the phase difference in the maxima and minima gets interchanged)

Now for constructive interference;

Δx= $(m+ \frac{1}{2} \lambda)$

replacing ;

Δx = 2t ; we have:

2t = $(m+ \frac{1}{2} \lambda)$

Given that thickness t = 700 nm

Then

2× 700 = $(m+ \frac{1}{2} \lambda)$ --- equation (1)

For thickness t = 980 nm that is next to constructive interference

2× 980 = $(m+ \frac{1}{2} \lambda)$ ----- equation (2)

Equating the difference of equation (2) and equation (1); we have:'

λ = (2 × 980) - ( 2× 700 )

λ = 1960 - 1400

λ = 560 nm

Thus; the wavelength λ of the light when it is traveling in air = 560 nm

b)

For the smallest thickness $t_{min} ; \ \ \ m =0$

∴ $2t_{min} =\frac{\lambda}{2}$

$t_{min} =\frac{\lambda}{4}$

$t_{min} =\frac{560}{4}$

$t_{min} =140 \ \ nm$

Thus, the smallest thickness t of the air film = 140 nm

7 0

4 years ago

Read 2 more answers

In an unweathered sample of igneous rock, the ratio of an unstable isotope to its stable daughter isotope is 1:15. If no daughte

svlad2 [7]

Answer:

200 million years

Explanation:

The equation that describes the decay of a radioactive isotope is

$N(t)=N_0 (\frac{1}{2})^{\frac{t}{t_{1/2}}}$

where

$N(t)$ is the amount of radioactive isotope left at time t

$N_0$ is the initial amount of isotope

$t_{1/2}$ is the half-life of the sample

In this problem, the ratio between unstable isotope and daughter isotope is 1:15; this means that

$\frac{N(t)}{N_0}=\frac{1}{16}$

Because the "total proportion" of original sample was 1+15=16.

Also we know that the half-life is

$t_{1/2}=50\cdot 10^6 y$

So we can re-arrange the equation to find t, the age of the rock:

$t=t_{1/2} log_{0.5}(\frac{N}{N_0})=(50\cdot 10^6)log_{0.5}(\frac{1}{16})=200\cdot 10^6 y$

So, 200 million years.

6 0

4 years ago

Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different direc

Lapatulllka [165]

Answer:

a) d = 30.79 m , b) θ = -22.4° , θ = 22.4 South of East

Explanation:

The easiest way to solve problems with vectors is to use their components, for this the East-West direction coincides with the x-axis and the North-South direction coincides with the y-axis

Let's use the index for / Ricardo and the index for Jane, let's break down the displacements

Richard

X axis

x₁ = 26.0 sin (60)

x₁ = -22.52 m

Y Axis

y₁ = 26.0 cos 60

y₁ = 13 m / s

Jane

X axis

x₂ = 16.0 cos (180 +30)

x₂ = -13.85 m

Y Axis

y₂ = 16.0 sin (180 + 30)

y₂ = - 8.0 m

Now we can use Pythagoras' theorem to find the distance between them

d = √ [(x₂ -x₁)² + (y₂ -y₁)²]

d = √ [(-13.85 + 22.52)² + (-8 -13)²]

d = 30.79 m

Let's use trigonometry to enter the address

tan θ = Δy / Δx

θ = tan⁻¹ Δy / Δx

θ = tan⁻¹ (-13.85 + 22.52) / (-8 - 13)

θ = tan⁻¹ (-8.67 / 21)

θ = -22.4°

The negative sign indicates that the angle is measured from the axis clockwise.

In the form of cardinal s point is

θ = 22.4 South of East

4 0

4 years ago

Multiple Choice

Andreas93 [3]

Acceleration of car is 4m/s²

Acceleration of truck is 2m/s²

Explanation:

Given parameters:

Force on the car and truck = 12000N

Mass of car = 3000kg

Mass of truck = 6000kg

Unknown:

Acceleration of car = ?

Acceleration of truck = ?

Solution:

Force is product of mass and acceleration. It is a push or a pull exerted on a body.

Force = mass x acceleration

Make acceleration the subject of the formula;

Acceleration = $\frac{Force}{mass}$

Acceleration of car = $\frac{12000}{3000}$ = 4m/s²

Acceleration of truck = $\frac{12000}{6000}$ = 2m/s²

learn more:

Acceleration brainly.com/question/3820012

Newton's law brainly.com/question/11411375

#learnwithBrainly

3 0

3 years ago