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3 years ago

Please help! This is for Algebra 1

Mathematics

1 answer:

kow [346]3 years ago

8 0

The first answer
-40y3/x5

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1. Solve each of the following addition and subtraction problems.

balandron [24]

A. 199

b. -71

c. -2.25

d. 30

e. -18

f. -4

g. 4

h. 7

i. 0

5 0

3 years ago

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

3 0

3 years ago

The local shelter decided to build an addition for cats hey borrowed $6300 from a local bank at a rate of 8% the high school hel

Zepler [3.9K]

Answer:

$378

Step-by-step explanation:

To find the interest that the shelter payed on this loan, we use the formula: $I=Prt$ .

P = $6,300

r = 8% or 0.08

t = 9/12

Now we substitute the values into our formula.

$I=Prt$ .

$I=6,300(0.08*\dfrac{9}{12})$

$I=6,300(0.08*0.75)$

$I=6,300(0.06)$

$I=$378$

So the shelter payed a total of $378 in interest to the bank.

3 0

3 years ago

2y + x + 7 = 0<br> how do i solve with substitution?

Jlenok [28]

Answer:

x+2y=-7

Step-by-step explanation:

2y + x =-7

x+2y=-7

6 0

3 years ago

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Give speed and position. be specific plz<br><br> y=-5x-1

Ann [662]

Speed is decreasing by 5 and position is -1

5 0

3 years ago