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Rashid [163]
2 years ago
6

Please answer need today.

Mathematics
2 answers:
marissa [1.9K]2 years ago
8 0
I can’t see the paper to good make it close
hoa [83]2 years ago
7 0

Answer:

dghfthbguknftyncdyjvceyjfawru

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HELP ASAP!!!!! PLEASE
Eva8 [605]

Find the area of the square, which has a side length of 2.

Area of square = 2 x 2 = 4  

Now multiply the area by the length b

Volume = 4 x 5 = 20 square units total.

8 0
3 years ago
y varies directly as x and inversely as the square of z. y equals y=30 when x equals x=108 and z equals z=6. Find y when x equal
Slav-nsk [51]

Answer:

Step-by-step explanation:

That really easy Peary it’s not eieoruirbcbdkehbdbs shrine chdiej

4 0
3 years ago
Please helpppp thank y’all
julsineya [31]

Answer:

105

Step-by-step explanation:

since its  a straight line it would add up to 180 degrees so 52 + 23 + 75 and you need 180 so 180-75 which gives 105 which is the missing angle

6 0
3 years ago
Read 2 more answers
Simplify 8a-5b-(6a-9b)
pychu [463]

Answer:

<h2>2(a + 2b)</h2>

Step-by-step explanation:

8a - 5b - (6a - 9b)

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression.

8a - 5b - 6a + 9b

Collect like terms

2a + 4b

Factor out 2 from the expression

2(a + 2b)

Hope this helps...

Good luck on your assignment..

7 0
3 years ago
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 8​% will need repairs​
Sladkaya [172]

Answer:

Probability that a car need to be repaired​ once = 20% = 0.20

Probability that a car need to be repaired​ twice = 8% = 0.08

Probability that a car need to be repaired​ three or more = 2% = 0.02

a) If you own two​ cars what is the probability that  neither will need​ repair?

Probability that a car need to be repaired​ once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair=0.7 \times 0.7=0.49

​b) both will need​ repair?

Probability both will need​ repair = 0.3 \times 0.3=0.09

c)at least one car will need​ repair

Neither car will need repair=0.7 \times 0.7=0.49

Probability that at least one car will need​ repair= 1-0.49 = 0.51

6 0
3 years ago
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