The Real Answer is B: Leasing a car for a certain period.
Hope this helps!
Answer:
$2,958.33
Step-by-step explanation:
Jasper's annual salary is $71000.
Considering that a year has 12 months and that he gets a paycheck twice each month, the total number of paychecks (P) Jasper gets each year is:
To define Jasper's gross income per paycheck (I), simply divide his annual salary by the number of paychecks in a year:
Jasper's gross income per paycheck is $2,958.33.
Answer:
7446.4375
Step-by-step explanation:
105.25
x 70.75
-------------
52625
First, we will want to start with the hundredths place. multiply 5×5. We get 25. Put the 5 down and carry the 2 above 2 in 105.25. Next, we multiply 2 in 105.25 with 5 in 70.75. 2×5 is 10, then we add the carried 2, and 10+2 is 12. We put the 2 down below, and carry the 1 above 5 in 105.25. Next, we multiply the 5 in 105.25 times 5. 5×5 is 25. We then need to add the carried 1 to 25 to get 26. We put the 6 down and put the 2 over 0 in 105.25. Next, we multiply 0 in 105.25 with 5 in 70.75. 0×5 is 0, plus our carried 2 from before, so 2. We don't need to carry anything since it's only the ones digit, so we put the 0 down. Next, we multiply the 1 in 105.25 with 5 again in 70.75. 1×5=5. Since we have no carries we can put the 5 down without adding anything. If this seemed confusing, let me simplify it for you. You basically start with the bottom number's "digit". For us, that's 70.75, and 5 would be the "digit." (The last digit from the bottom number.) We then multiply this "digit" by every number from the top number's digits. For example, we'd multiply 70.75's 5, with 105.25's 5 first, then continue on going left from there. I hope this helped! If it just confused you more please let me know. (Also remember to put a 0 when you start multiplying with your second digit on the bottom number)
Answer:
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Answer:
5. 1
6. Kari is not correct.
Step-by-step explanation:
5. All like terms can be combined. There will be one term remaining after they are.
___
6. The appropriate factoring is x(x+1). This is not the same as x(2x+1).
In order to show equivalence, you need to show that the expressions produce the same result for as many different values of x as the degree of the expression plus 1. That is, you'd need to show equivalence for <em>3 different values of x</em>, as a minimum for this second-degree expression.
