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lesantik [10]
3 years ago
15

Which conditional statement has a converse that is true?

Mathematics
2 answers:
EastWind [94]3 years ago
4 0
If I'm running then I'm exercising

Converse if I'm exercising then I'm running not necessarily maybe your jogging or another exercise

If I'm awake then I'm studying
Convers if I'm studying then I'm awake .since you have to be awake in order to study this is the one that's the right answer
slava [35]3 years ago
3 0

Answer: If I am running, then I am exercising.

Reasoning: When you run, you are using your muscles to make your heart beat faster and lungs expand harder, which is part of cardiovascular exercise.

If you are awake, you aren't always studying. You can be awake and go to the beach or play video games in your room. Although, in a way, you are studying something when playing video games. You are studying the game's mechanics and how the game works.

If you are in the desert, you aren't always thirsty unless you haven't drank anything for a long time. You could be chugging down gallons of water throughout the trip through the desert and not be thirsty.

If you are biking, you aren't always moving. There are times where you will have to stop to repump your tires or stop at stop lights/signs.

If you are running, you are exercising your legs, heart, lungs, core muscles, and sometimes your stomach if you're running up a hill.

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A turtle and a snail are 300 feet apart when they start moving towards each other. The turtle is moving at a speed of 5 feet per
givi [52]

Answer:

It Is 60

Step-by-step explanation:

300/5=60x1=60

3 0
3 years ago
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1/2(8-x)=10<br> A.12<br> B.3<br> C.-12
Murljashka [212]
4-1/2x=10
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so your answer would be B
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7 0
3 years ago
Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.
GREYUIT [131]

Answer:

y=\dfrac{1}{1-Ke^{-t}}

Step-by-step explanation:

Given

The given equation is a differential equation

\dfrac{dy}{dt}=y-y^2

\dfrac{dy}{dt}=-(y^2-y)

By separating variable

⇒\dfrac{dy}{(y^2-y)}=-t

\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt

Now by taking integration both side

\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt

⇒\ln (y-1)-\ln y=-t+C

Where C is the constant

\ln \dfrac{y-1}{y}=-t+C

\dfrac{y-1}{y}=e^{-t+c}

\dfrac{y-1}{y}=Ke^{-t}

y=\dfrac{1}{1-Ke^{-t}}

from above equation we can say that

When t  will increases in positive direction then e^{-t} will decreases it means that {1-Ke^{-t}} will increases, so y will decreases. Similarly in the case of negative t.

4 0
3 years ago
Help me yall this for me aint it.
aleksandrvk [35]

Answer:

20(4 + 5)

Step-by-step explanation:

GCF is just the biggest number each value can be divided by. Here, it's 20, so that goes outside of the parenthesis. Now, what can you multiply by 20 to get 80? 4, so that goes in the second box. What can you multiply by 20 to get 100? 5, so that goes in the last box. You can check your answer by doing 80 + 100 = 180; 20(9) = 180.

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3 years ago
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How much would a 10th dog have to weight for the average weight in part (a)
andreyandreev [35.5K]

132LB

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