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garri49 [273]
3 years ago
7

Pls helppppp! I'll give brainliest :)) 1/3y+6-2/3y

Mathematics
1 answer:
Vitek1552 [10]3 years ago
5 0

Answer: 5.66666666667

Step-by-step explanation: Thanks and have a Savage day.

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Find the sum of the first six terms of a geometric series in which a1 = 4 and r = -3: A. 729 B. -729 C. -728 D. 728 plz help
natta225 [31]

Answer:

C

Step-by-step explanation:

The sum to n terms of a geometric sequence is

S_{n} = \frac{a_{1}(r^n-1) }{r-1}

Here a₁ = 4 and r = - 3, thus

S_{6} = \frac{4((-3)^6-1)}{-3-1}

    = \frac{4(729-1)}{-4} = - (729 - 1) = - 728 → C

6 0
3 years ago
The running shoes Gina bought at a 20%-off sale were originally priced at $70. Before tax was added, how much money did Gina sav
il63 [147K]

gina saved $14

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8 0
3 years ago
Solve the system of equations. x + 3y= -8 4x + 4y = 0​
Evgesh-ka [11]

Answer:

x = -3

y = 4

Step-by-step explanation:

6 0
3 years ago
((-2^2)(-1^-3))•((-2^-3)(-1^5))^-2
Vitek1552 [10]

Answer:

  256

Step-by-step explanation:

A calculator works well for this.

_____

None of the minus signs are subject to the exponents (because they are not in parentheses, as (-1)^5, for example. Since there are an even number of them in the product, their product is +1 and they can be ignored.

1 to any power is still 1, so the factors (1^n) can be ignored.

After you ignore all of the things that can be ignored, your problem simplifies to ...

  (2^2)(2^-3)^-2

The rules of exponents applicable to this are ...

  (a^b)^c = a^(b·c)

  (a^b)(a^c) = a^(b+c)

Then your product simplifies to ...

  (2^2)(2^((-3)(-2)) = (2^2)(2^6)

  = 2^(2+6)

  = 2^8 = 256

3 0
3 years ago
Two dice are tossed. Find the probability of getting the sum of the dice equal to 28.
dimulka [17.4K]

Answer:

Isn't the sum when you add numbers together? if this is true, there is no way you can get the sum of 28

Step-by-step explanation:

3 0
3 years ago
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