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Zina [86]
3 years ago
5

Solve the inequality: x^2 - 2.2x + 1.21

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0
No solution / no x

D=b^2-4*a*c -> D=-4^2-4*1*21 -> D=-28 -> D<0, no solution
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I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
What is the number two hundred seven thousand, four hundred sixty written in standard form?
Zinaida [17]

Answer:

207,460

Step-by-step explanation:

brainiest plz

5 0
3 years ago
CAN SOMEONE PLEASE HELP ME DO THE EQUATION
valina [46]

y=2/5x


5y=2x

so y=2x÷5=2/5x

7 0
3 years ago
96.3kg= g Complete the statement.
Kay [80]

Answer:

96.3Kg = 96,300g

Step-by-step explanation:

1 Kg is equivalent to 1,000 g

4 0
3 years ago
Read 2 more answers
Let’s pretend that we want to give our employees in total a28% raise in the next two years, but we want to spread out aconsisten
Roman55 [17]

Solution

- The solution steps are given below:

\begin{gathered} \text{ Let the original amount be X} \\  \\ \text{ If we want a 28\% raise over the next two years, then it means that the amount will be:} \\ X+\frac{28}{100}X=1.28X \\  \\ \text{ If we want to give them a consistent raise each year, we can compute the scenario as follows:} \\ \text{ Let the percentage be }y \\  \\ X+y\%\text{ of }X=\text{ Salary after first year} \\  \\ (X+y\%\text{ of }X)+y\%\text{ of }(X+y\%\text{ of }X)\text{ = Salary after second year.} \\  \\ \text{ But we already know that the salary after second year is }1.28X \\ \text{ Thus, we can say:} \\ (X+y\%\text{ of }X)+y\%\text{ of }(X+y\%\text{ of }X)=1.28X \\  \\ \text{ Simplifying, we have:} \\ X+\frac{yX}{100}+\frac{y}{100}(X+\frac{yX}{100})=1.28X \\  \\ \text{ Divide through by }X \\ 1+\frac{y}{100}+\frac{y}{100}(1+\frac{y}{100})=1.28 \\  \\ \text{ Subtract 1 from both sides and expand the brackets} \\ \frac{y}{100}+\frac{y}{100}+(\frac{y}{100})^2=1.28-1=0.28 \\  \\ \frac{2y}{100}+(\frac{y}{100})^2=0.28 \\  \\ \text{ Multiply both sides by }100^2 \\ 200y+y^2=2800 \\  \\ \text{ Rewrite, we have:} \\ y^2+200y-2800=0 \\  \\ Solving\text{ the equation using the Quadratic formula, we have that:} \\ y=\frac{-200\pm\sqrt{200^2-4(-2800)}(1)}{2(1)} \\  \\ y=-213.137\text{   or   }13.137 \\  \\ \text{ Since the change in salary is an increase, thus, the rate }y\text{ has to be positive.} \\ \text{ Thus, } \\ y=13.137\approx13.14\% \\  \\  \end{gathered}

Final Answer

y = 13.14%

The screenshots of the solution are:

5 0
1 year ago
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