Answer:
See description below.
Step-by-step explanation:
To choose the correct equation, find the slope of the line on the graph. Identify two points on the line. Then subtract to find their rate of change using the slope formula.
When you know the slope, find the negative reciprocal. For example, if the slope is 2/1 then the negative reciprocal is -1/2. This is the slope of a perpendicular line to a line with slope 2. Choose the equation which has this same slope.
Example:
y = 2x -1
y= -1/2 +5
Two visits are from the fire inspector and four visits are from the health inspector in 30 days both inspectors will visit on the same day
Answer:
1. y = 14.718
2. ??
3. y = 39.794°
Step-by-step explanation:
<em>HINT the side we already know and the side we are trying to find, we use the first letters of their names and the phrase "SOHCAHTOA" to decide which function:
</em>
SOH...
Sine: sin(θ) = Opposite / Hypotenuse
...CAH...
Cosine: cos(θ) = Adjacent / Hypotenuse
...TOA
Tangent: tan(θ) = Opposite / Adjacent
1. Sine: sin(θ) = Opposite / Hypotenuse
sin(42°) = y / 22
so on your calculator enter 42 then sin = 0.669
0.669 = y/22 multiply both sides by 22 to get y
y = 14.718
2. is there any other information??
3. The two sides we know are Opposite 40 and Adjacent 48.
SOHCAHTOA tells us we must use Tangent.
Calculate Opposite/Adjacent = 40/48 = 0.833
Find the angle from your calculator using tan-1
Tan y° = opposite/adjacent = 40/48 = 0.833
tan-1 of 0.833 = 39.794°
Answer:
No he can not because if you add 0 to 52 you get 520 and the answer has to be 520
Step-by-step explanation:
<h3>
Answer:</h3>
sin(Y) = 4/5
<h3>
Step-by-step explanation:</h3>
The sine of one of a pair of complementary angles is equal to the cosine of the other. Given that ∠X and ∠Y are complementary, sin(Y) = cos(X) = 4/5.
_____
You can figure this from SOH CAH TOA, the mnemonic that reminds you of the definitions of the trig functions. The adjacent leg for one of the acute angles in the right triangle is the opposite leg for the other angle.
... Sin = Opposite/Hypotenuse
... Cos = Adjacent/Hypotenuse
