All categories

3 years ago

(5) in simplist fraction form

Mathematics

2 answers:

MrRissso [65]3 years ago

7 0

What?
(5) in simplest fraction form is 5/1.

mario62 [17]3 years ago

4 0

5 in fractional form is 5/1.

You might be interested in

(4x + 8x - 5) + (3x2 + 6x - 7)

ch4aika [34]

Answer:

7x^2 + 14x - 12

Step-by-step explanation:

Add like terms:

(4x + 8x - 5) + (3x2 + 6x - 7) becomes:

4x^2 + 8x - 5 or (grouping like terms in columns):

+ 3x^2 + 6x - 7

---------------------

7x^2 + 14x - 12

5 0

3 years ago

5. An angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 5 cm long. A second side of

Umnica [9.8K]

This is not my work but i hope this can help you with your problem
https://answers.yahoo.com/question/index?qid=20120518194118AAhi738

7 0

3 years ago

Read 2 more answers

For the graph shown, select the statement that best represents the given system of equations. Number graph ranging from negative

Bumek [7]

This system of equations is consistent and independent, because there is only one solution. the answer is C

7 0

3 years ago

Read 2 more answers

M - 7 < 6 please help me

Citrus2011 [14]

<span>the answer is M<13 for problems like this you can go to https://www.cymath.com/answer.php?q=solve%20M%20-%207%3C%206 to solve your answer</span>

7 0

3 years ago

Ponderosa Paint and Glass carries three brands of paint. A customer wants to buy another gallon of paint to match paint she purc

sveta [45]

Answer:

$\frac{4}{9}$

Step-by-step explanation:

Two events are independent of each other, this is called Compound Probability. Classical example is if two coins are filped, what is the probability of getting two heads in a row.?

Answer: each has 50% probability because there are two states only, either H or T. since we have two coins the probability of getting two heads in row is the product of obtaining heads for each individual coin (which is independent of each other). or is $\frac{1}{2}$ × $\frac{1}{2}$ = $\frac{1}{4}$ = 25%. (Notice!).

Back to our problem, now here we have 3 paint brands and one of them is the right paint brand and two of them are not correct brands. so the prabablity that the customer has picked not correct brand is $\frac{2}{3}$ and her husband has not picked correct brand is also $\frac{2}{3}$ , since two probabilities are compound probabilities i.e indepandant of each other the probablity that both woman and her husband fail get correct brand is the product of the two and is = $\frac{2}{3}$ × $\frac{2}{3}$ = $\frac{4}{9}$ .

4 0

3 years ago