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cricket20 [7]
3 years ago
11

BRAINLIEST!!!!!!please hurry!!!!!what is 3+4(74-32)+89

Mathematics
2 answers:
Alchen [17]3 years ago
7 0

Answer:

260

Step-by-step explanation:

3+4(42)+89

3+168+89

260

ipn [44]3 years ago
3 0

Answer:

260

Step-by-step explanation:

Work in the parentheses first; 74-32 is 42. Then work with multiplication, 42 times 4 is 168. 168+89+3 = 260

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-3 3/7 divided by 4 2/7=???
nadezda [96]

the answer will be -0.8, if i helped thank you

8 0
3 years ago
Read 2 more answers
What is the constant of proportionality of a graph if x equals 3 and y equals 90?
solmaris [256]
y = kx

'k' is the constant of proportionality, or otherwise known as constant of variation. 

y = 90
x = 3

90 = k(3)
90 = 3k
3k/3 = 90/3
k = 30

The constant of proportionality is 30. 
6 0
3 years ago
Find MO and PR <br> ............................................................
ddd [48]

MO = 12 and PR = 3

Solution:

Given \triangle M N O \sim \Delta P Q R.

Perimeter of ΔMNO = 48

Perimeter of ΔPQR = 12

MO = 12x and PR = x + 2

<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>

$\Rightarrow \frac{\text{Perimeter of }\triangle MNO}{\text{Perimeter of }\triangle PQR} =\frac{MO}{PR}

$\Rightarrow \frac{48}{12} =\frac{12x}{x+2}

Do cross multiplication.

$\Rightarrow 48({x+2})= 12(12x)

$\Rightarrow 48x+96= 144x

Subtract 48x from both sides.

$\Rightarrow 48x+96-48x= 144x-48x

$\Rightarrow 96= 96x

Divide by 96 on both sides, we get

⇒ 1 = x

⇒ x = 1

Substitute x = 1 in MO an PR.

MO = 12(1) = 12

PR = 1 + 2 = 3

Therefore MO = 12 and PR = 3.

7 0
3 years ago
Please help me, I'm a little confused on this one.
pochemuha
The answer is D , because if you look on the graph you going to see the Answer in your face
7 0
4 years ago
The length of a rectangular field is 6 metres longer than its width. If the area of the field is 72 square metres, What are the
True [87]

Answer:

Let's call the length of the field "l", and the width of the field "w".

If the area of the field is 72 square meters, then we have:

l x w = 72

And if the length is 6 meters longer than the width, we have:

l = w+6

So looking at the first equation (l x w = 72), we can substitute the l for a w+6.

And we obtain:

(w+6) x (w) = 72

Which simplifies to w^2 + 6w = 72.

This quadratic equation is pretty easy to solve, you just need to factor it.

w^2 + 6w - 72 = 0

(w-6)(w+12)

This leaves the roots of the  quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.

So, the width of the rectangular field is 6, and the length of the field is 12.

Let me know if this helps!

5 0
3 years ago
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