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alex41 [277]
3 years ago
14

Carly paid $17.50 for 7 gallons of gas and Jade paid $45 for 15 gallons of gas. Which of the following statements is true?

Mathematics
1 answer:
KatRina [158]3 years ago
3 0

Answer:

Jade paid more per gallon than Carly

Step-by-step explanation:

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9.433<br> 9.4<br> 9.37 9.311<br> 9.345<br> 9.35<br> Least to greatest
faust18 [17]

Answer:

LEAST

9.311

9.345

9.35

9.37

9.4

9.433

GREATEST

Step-by-step explanation:

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5 0
3 years ago
2³- (3x5²)<br> PLEASE HELP 20 POINTS , also show ur work, thank u sm!
Alexxx [7]

Answer:

-67

Step-by-step explanation:

2^3-(3*5^2)

simplify exponents

8-3*25

8-75

=-67

3 0
3 years ago
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Only answer if you know! no spams :)
artcher [175]

Answer:

The correct answer is C.

Step-by-step explanation:

There are 8 slots on Spinner B.

3 of those slots have squares.

Hence out of all the slots, 3/8 of them have squares.

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5 0
2 years ago
Read 2 more answers
A ship leaves port at 10 miles per hour, with a heading of N 35° W. There is a warning buoy located 5 miles directly north of th
Leno4ka [110]

The value of the angle subtended by the distance of the buoy from the

port is given by sine and cosine rule.

  • The bearing of the buoy from the is approximately <u>307.35°</u>

Reasons:

Location from which the ship sails = Port

The speed of the ship = 10 mph

Direction of the ship = N35°W

Location of the warning buoy = 5 miles north of the port

Required: The bearing of the warning buoy from the ship after 7.5 hours.

Solution:

The distance travelled by the ship = 7.5 hours × 10 mph = 75 miles

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Where;

a = The distance between the ship and the buoy

b = The distance between the ship and the port = 75 miles

c = The distance between the buoy and the port = 5 miles

Angle ∠A = The angle between the ship and the buoy = The bearing of the ship = 35°

Which gives;

a = √(75² + 5² - 2 × 75 × 5 × cos(35°))

By sine rule, we have;

\displaystyle \frac{a}{sin(A)} = \mathbf{ \frac{b}{sin(B)}}

Therefore;

\displaystyle sin(B)= \frac{b \cdot sin(A)}{a}

Which gives;

\displaystyle sin(B) = \mathbf{\frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }}

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx 37.32^{\circ}

Similarly, we can get;

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx \mathbf{ 142.68^{\circ}}

The angle subtended by the distance of the buoy from the port, <em>C</em> is therefore;

C ≈ 180° - 142.68° - 35° ≈ 2.32°

By alternate interior angles, we have;

The bearing of the warning buoy as seen from the ship is therefore;

Bearing of buoy ≈ 270° + 35° + 2.32° ≈ <u>307.35°</u>

Learn more about bearing in mathematics here:

brainly.com/question/23427938

5 0
2 years ago
How many numbers are equal to the sum of two odd, one-digit numbers?
Dennis_Churaev [7]

Answer:

Seven numbers.

Step-by-step explanation:

Finding the numbers, which are equal to the sum of two odd number and it has to be single digit number.

Lets look into numbers which are odd and single digit.

1 = 1+3, 1+5, 1+7, 1+9

∴ Sum of the number is 4,6,8\ and\ 10

3 = 3+5, 3+7, 3+9

∴ Sum of above number is 8,10\ and\ 12

5 = 5+7, 5+9

∴ Sum of above number is 12\ and\ 14

7= 7+9

∴ Sum of above number is 16

Now, accumlating numbers which are fullfiling the criteria, however, making sure no number should get repeated.

∴ Numbers are: 4,6,8,10,12,14\ and\ 16

Hence, there are total 7 numbers, which  are equal to the sum of two odd, one-digit numbers.

4 0
3 years ago
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