12 + 90
GCF = 6
12/6 = 2
90/6 = 15
(6 * 2) + (6 * 15) =
6(2 + 15) <====
Answer:
21 child tickets.
Step-by-step explanation:
Let x represent number of adult tickets and y represent number of child tickets.
We have been given that on Thursday, three times as many adult tickets as child tickets were sold. We can represent this information in an equation as:

We have been given that at a the movie theater, child admission is $6.10 and adult admission is $9.20.The all tickets were sold for a total of $707.70. We can represent this information in an equation as:
Upon substituting equation (1) in equation (2), we will get:




Therefore, 21 child tickets were sold on Thursday.
<span>To find the number of nickels and dimes, we can use this equation: 0.10d + 0.05n = 5.25
We are given the information that Sonji has 21 dimes (which means that d=21). We can use the equation to find the number of nickels n.
0.10d + 0.05n = 5.25
0.10(21) + 0.05n = 5.25
2.10 + 0.05n = 5.25
0.05n = 3.15
n = 3.15 / 0.05
n = 315 / 5
n = 63
Sonji has 63 nickels.
Let's check our answer.
21(0.10) + 63(0.05) = 2.10 + 3.15 = 5.25
It seems that our answer is correct.</span>
The volume of a cone is one-third of the product of the area of the base times the height, i.e.
(1/3)π(r^2)*h = (1/3)π(3cm)^2 *(8cm) = 75.40 cm^3
Now multiply that by the number of cones: 6 * 75.40 cm^3 = 452.40 cm^3.
Then the answer is 452 cm^3