Question

find the probability of exactly two successes in five trials of a binomial experiment in which the probability of success is 50%

Answer 1

ANSWER: 31.25%

Explaination:

Suppose (x+y)$(x+y)^{5}$ is the binomial distribution with 5 trials. Given that, probability of exactly two success in five trials of a binomial experiment in which the probability of success is 50%.

So, x = 0.5 and y = 0.5

The term

5C2*x²*y³ representing 2 successes and 3 failures.

Now find the value of this term.

5C2*(0.5)²*(0.5)³ = $\frac{5!}{2!3!}$*$(0.5)^{5}$

=10*0.03125

= 31.25%