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Vilka [71]
3 years ago
12

Yes or no???????????

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
3 0
No
a^2 + b^2 does not equal c^2
15^2 + 18^2 = 549
22^2 = 484
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The scatter plot below shows the number of enrollments, N, in a sports club, t years after the year 2005.
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Determine the dimensions of a rectangular solid (with square base) with a maximum volume if its surface are is 337.5 square cent
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Qᴜɪᴢ-<br><br> What is <img src="https://tex.z-dn.net/?f=y%20~%2B~3y%20%3D%200%20~%2B~24" id="TexFormula1" title="y ~+~3y = 0 ~+~
zhuklara [117]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • What is \tt\:y+3y=0+24? Explain it.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

\tt \: y + 3 y = 0 + 24

Combine y and 3y to get 4y.

\tt \: 4y=0+24

Add 0 and 24 to get 24.

\tt \: 4y=24

Divide both sides by 4.

\tt \: y=\frac{24}{4}  \\

Divide 24 by 4 to get 6.

\boxed { \boxed {\bf \: y=6 }}

8 0
3 years ago
A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters
natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that p = 0.7

20 eligible voters were randomly selected from the population of all eligible voters.

This means that n = 20

What is the probability that fewer than 11 of them will vote?

This is:

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308

P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120

P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039

P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010

P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002

P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479

0.0479 = 4.79% probability that fewer than 11 of them will vote

8 0
3 years ago
points) Thursday, September 2, 2021 01:55 PM EDT Andrew has nine fewer coins than Casey. Bob has three more than twice as many c
swat32

Answer:

Andrew: 131 coins Bob: 265 coins Casey: 145 coins

Step-by-step explanation:

3 0
3 years ago
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