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ANTONII [103]
4 years ago
8

What is the equation of a line passing through the point (4,-1) and parallel to the line whose equation is 2y-x=8

Mathematics
1 answer:
Ksivusya [100]4 years ago
4 0

9514 1404 393

Answer:

  2y -x = -6

Step-by-step explanation:

You can use the same x- and y-coefficients. You just have to change the constant on the right. Put the point values into the left expression to see the new constant.

  2y -x = 2(-1)-(4) = -6

The parallel line is ...

  2y -x = -6

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What are the maximum and minimum of the function f(x) = 0.9 I -(x - 5) I + 7 ? A. Maximum at (5,7) and minimum at (0,0) B. Minim
user100 [1]

Answer:

Minimum = (5,7)

No maximum

Step-by-step explanation:

Given

f(x) = 0.9|-(x - 5)| + 7

Solving (a): The minimum

The minimum is when the absolute parameter gives 0

i.e.

0.9|-(x - 5)| =0

Divide both sides by 0.9

|-(x - 5)| =0

Open bracket

|-x + 5| =0

Remove absolute sign

-x + 5 =0

Collect like terms

x = 5

Then the y value is:

f(x) = 0.9|-(x - 5)| + 7

Recall that: 0.9|-(x - 5)| =0

So, we have:

f(x) = 0 + 7

f(x) = 7

Hence, the minimum is at: (5,7)

Since the minimum is at (5,7), then the graph will open upwards.

Hence. the function has no maximum; i.e.

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7 0
3 years ago
Hi! Im stuck on this question (Its attatched) and I dont know how to answer it.
Ksju [112]

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3 years ago
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