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ANTONII [103]
4 years ago
8

What is the equation of a line passing through the point (4,-1) and parallel to the line whose equation is 2y-x=8

Mathematics
1 answer:
Ksivusya [100]4 years ago
4 0

9514 1404 393

Answer:

  2y -x = -6

Step-by-step explanation:

You can use the same x- and y-coefficients. You just have to change the constant on the right. Put the point values into the left expression to see the new constant.

  2y -x = 2(-1)-(4) = -6

The parallel line is ...

  2y -x = -6

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x/5 = 20 Answer: x = 100

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5x = 55 Answer: x = 11

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4 years ago
Who goes to Edgewood Middle School in Ninety Six SC
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
AYE PLS HELP ASAP !! MARKIN DA BRAINIEST !!!
DIA [1.3K]

Answer:

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y ≤ -x + 55       --------(1)

y > -1.5 x + 15  -------(2),

The related line of the inequality (1) is,

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Which having x-intercept = (55,0)

And, y-intercept = (0,55),

Also, at (0,0),

Inequality (1), 0 ≤ 0 + 55 ( True )

Thus, it will contain the origin,

Also, ≤ sign stated that the inequality (1) is a solid line,

Now, The related line of the inequality (2) is,

y =  -1.5 x + 15 -----(3)

Which having x-intercept = (10,0)

And, y-intercept = (0,15),

Also, at (0,0),

Inequality (1), 0 > 0 + 15 ( False )

Thus, it will not contain the origin,

Also, > sign stated that the inequality (2) is a dashed line,

Now after solving equation (3) and (4) we get,

x = -80 and y = 135

⇒ The intersection point of line (3) and (4) is (-80,135)

Hence, by the above explanation we can plot the given system of inequalities ( Shown below )

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Answer:

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Step-by-step explanation:

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yanalaym [24]

Answer:

Diameter is 11cm, and the radius is 5.5

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