Question

How would I solve this question

Answer 1

Tan(ANGLE) = Opposite Leg / Adjacent Leg

Tan(60) = Y/8

Y = 8 x tan(60)

Y = 8√3

Y = 13.9

Answer 2

$tangent=\dfrac{opposite}{adjacent}\\\\\tan60^o=\dfrac{y}{8}\ \ \ |\tan60^o=\sqrt3\\\\\dfrac{y}{8}=\sqrt3\ \ \ \ |\cdot8\\\\\boxed{y=8\sqrt3}\to\boxed{y\approx13.9}$

Other method.

Two such triangles form an equilateral triangle (look at the picture).

The formula of a height of an equilateral triangle:

$h=\dfrac{a\sqrt3}{2}$

We have

$a=2\cdot8=16;\ h=y$

Substitute:

$y=\dfrac{16\sqrt3}{2}=8\sqrt3\approx13.9$