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statuscvo [17]
3 years ago
11

For the polynomial below, find F(0.5). Round your answer to the nearest hundredth.

Mathematics
2 answers:
marissa [1.9K]3 years ago
7 0
\bf f(x)=2x^2-3x+15\qquad f(0.5)\qquad 
\begin{cases}
0.5\iff \frac{1}{2}
\end{cases}
\\\\
\textit{let us use }\frac{1}{2}
\\\\
f\left( \frac{1}{2} \right)=2\left( \frac{1}{2} \right)^2-3\left( \frac{1}{2} \right)+15\to 2\cdot \cfrac{1^2}{2^2}-\cfrac{3}{2}+15\to 2\cdot \cfrac{1}{4}-\cfrac{3}{2}+15
\\\\\\
f\left( \frac{1}{2} \right)=\cfrac{1}{2}-\cfrac{3}{2}+15\to -\cfrac{2}{2}+15\to -1+15\to 14
alexdok [17]3 years ago
6 0
No it is not correct the answer is 14!

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Answer

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Explanation

Area of the rectangle given = 50 ft²

Let the width of the rectangle be x

So this means the length of the rectangle will be 3x - 5

What to find:

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Step-by-step solution:

Area of a rectangle = length x width

i.e A = L x W

Put A = 50, L = 3x - 5, W = x into the formula.

\begin{gathered} 50=(3x-5)x \\ 50=3x^2-5x \\ 3x^2-5x-50=0 \end{gathered}

The quadratic equation can now be solve using factorization method:

\begin{gathered} 3x^2-5x-50=0 \\ 3x^2-15x+10x-50=0 \\ 3x(x-5)+10(x-5)=0 \\ (3x+10)(x-5)=0 \\ 3x+10=0\text{ }or\text{ }x-5=0 \\ 3x=-10\text{ }or\text{ }x=5 \\ x=-\frac{10}{3}\text{ }or\text{ }x=5 \end{gathered}

Since the dimension can not be negative, hence the value of x will be = 5.

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\begin{gathered} Length=3x-5=3(5)-5=15-5=10\text{ }ft \\  \\ Width=x=5\text{ }ft \end{gathered}

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1 year ago
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<em>Answer:</em>

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<em>Step-by-step explanation:</em>

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