Question

For the polynomial below, find F(0.5). Round your answer to the nearest hundredth.

Answer 1

$\bf f(x)=2x^2-3x+15\qquad f(0.5)\qquad \begin{cases} 0.5\iff \frac{1}{2} \end{cases} \\\\ \textit{let us use }\frac{1}{2} \\\\ f\left( \frac{1}{2} \right)=2\left( \frac{1}{2} \right)^2-3\left( \frac{1}{2} \right)+15\to 2\cdot \cfrac{1^2}{2^2}-\cfrac{3}{2}+15\to 2\cdot \cfrac{1}{4}-\cfrac{3}{2}+15 \\\\\\ f\left( \frac{1}{2} \right)=\cfrac{1}{2}-\cfrac{3}{2}+15\to -\cfrac{2}{2}+15\to -1+15\to 14$

Answer 2

No it is not correct the answer is 14!