Mr. Lamb built a stone walkway in his back yard. Each stone was 5/6 foot long. How many stones did it take him if the walkway wa
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The weight of the new student is 27 kg.
Average weight
= total weight ÷total number of students
<h3>1) Define variables</h3>Let the total weight of the 35 students be y kg and the weight of the new student be x kg.
<h3>2) Find the total weight of the 35 students</h3><u></u>
y= 35(45)
y= 1575 kg
<h3>3) Write an expression for average weight of students after the addition of the new student</h3>New total number of students
= 35 +1
= 36
Total weight
= total weight of 35 students +weight of new students
= y +x
36(44.5)= 1575 +x
1602= x +1575
<em>Subtract 1575 from both sides:</em>
x= 1602 -1575
x= 27
Thus, the weight of the new student is 27 kg.
Answer:
w < 8 meters ( w must be greater than 0 because length cannot be 0)
Step-by-step explanation:
One side with building is 23 meters, the other opposite side also will be 23 meters (with rope).
Let width (remaining 2 sides) be "w", he has AT MOST 39 meters of rope, so we can write:
Rope Needed = 23 + 2w < 39
Simplifying:
The range of possible values of w is meters (of course w has to be greater than 0)