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EastWind [94]
2 years ago
7

Question 6

Mathematics
1 answer:
inna [77]2 years ago
7 0

Answer:

add, subtract, multiply and divide complex numbers much as we would expect. We add and subtract

complex numbers by adding their real and imaginary parts:-

(a + bi)+(c + di)=(a + c)+(b + d)i,

(a + bi) − (c + di)=(a − c)+(b − d)i.

We can multiply complex numbers by expanding the brackets in the usual fashion and using i

2 = −1,

(a + bi) (c + di) = ac + bci + adi + bdi2 = (ac − bd)+(ad + bc)i,

and to divide complex numbers we note firstly that (c + di) (c − di) = c2 + d2 is real. So

a + bi

c + di = a + bi

c + di ×

c − di

c − di =

µac + bd

c2 + d2

¶

+

µbc − ad

c2 + d2

¶

i.

The number c−di which we just used, as relating to c+di, has a spec

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Can someone help me with this and show me how to do it?
densk [106]

9514 1404 393

Answer:

  5i) f(x) = 3·13^x +5

  5ii) f(x) = -6·(1/2)^x +5

  6) f(x) = 3·8^x -1

  9a) (1, 0), (0, -3)

  9b) (2, 0), (0, 8)

Step-by-step explanation:

5. The horizontal asymptote is y = c. To meet the requirements of the problem, you must choose c=5 and any other (non-zero) numbers for 'a' and 'b'. (You probably want 'b' to be positive, so as to avoid complex numbers.)

i) f(x) = 3·13^x +5

ii) f(x) = -6·(1/2)^x +5

__

6. You already know c=-1, so put x=0 in the equation and solve for 'a'. As in problem 5, 'b' can be any positive value.

  f(0) = 2 = a·b^0 -1

  3 = a

One possible function is ...

  f(x) = 3·8^x -1

__

9. The x-intercept is the value of x that makes y=0. We can solve for the general case:

  0 = a·b^x +c

  -c = a·b^x

  -c/a = b^x

Taking logarithms, we have ...

  log(-c/a) = x·log(b)

  \displaystyle x=\frac{\log\left(-\dfrac{c}{a}\right)}{\log(b)}=\log_b\left(-\dfrac{c}{a}\right)

Of course, the y-intercept is (a+c), since the b-factor is 1 when x=0.

a) x-intercept: log2(6/3) = log2(2) = 1, or point (1, 0)

   y-intercept: 3-6 = -3, or point (0, -3)

b) x-intercept: log3(9/1) = log3(3^2) = 2, or point (2, 0)

  y-intercept: -1 +9 = 8, or point (0, 8)

_____

<em>Additional comment</em>

It is nice to be comfortable with logarithms. It can be helpful to remember that a logarithm is an exponent. Even so, you can solve the x-intercepts of problem 9 using the expression we had just before taking logarithms.

  a) 6/3 = 2^x   ⇒   2^1 = 2^x   ⇒   x=1

  b) -9/-1 = 3^x   ⇒   3^2 = 3^x   ⇒   x=2

5 0
2 years ago
The base of 40-foot ladder is 8 feet from the wall. How high is the ladder on the wall (round to the nearest foot)
Nina [5.8K]

Given:

The base of 40-foot ladder is 8 feet from the wall.

To find:

How high is the ladder on the wall (round to the nearest foot).

Solution:

Ladder makes a right angle triangle with wall and ground.

We have,

Length of ladder (hypotenuse)= 40 foot

Base = 8 foot

We need to find the perpendicular to get the height of the ladder on the wall.

Let h be the height of the ladder on the wall.

According to the Pythagoras theorem,

Hypotenuse^2=Base^2+Perpendicular^2

(40)^2=(8)^2+(h)^2

1600=64+h^2

1600-64=h^2

1536=h^2

Taking square root on both sides.

\pm \sqrt{1536}=h

\pm 39.1918358=h

Height cannot be negative. Round to the nearest foot.

h\approx 39

Therefore, the height of the ladder on the wall is 39 foot.

5 0
3 years ago
Using n for the number of jerseys ordered and c for the total cost in dollars,
mr Goodwill [35]

Answer:

98$

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Peter hired a cleaning company to clean his house. The cleaning company charges a fixed fee $15 plus $17 per hour to clean a hou
Mumz [18]
What’s the question?
6 0
2 years ago
Evaluate the function found in the previous step at X =-3
babunello [35]
x-5y=-4x-2y

In order to evaluate the given function at x = -3, simply replace "x" in the function with -3 and solve.

-3-5y=-4(-3)-2y

<em>Multiply -4 and -3 in the function above.</em>

-3-5y=12-2y

<em>Add 3 on both sides of the equation.</em>

-3-5y+3=12-2y+3-5y=15-2y

<em>Add 2y on both sides of the equation.</em>

-5y+2y=15-2y+2y-3y=15

<em>Divide both sides of the equation by -3.</em>

\frac{-3y}{-3}=\frac{15}{-3}y=-5

Therefore, at x = -3, the value of y = -5. Hence, f(-3) = -5.

Answer:

f(-3) = -5

<em />

7 0
1 year ago
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