That'd be a total of 6 km east and 4 km north.
The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.
However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:
sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km
D because the submarine started at sea level and ended 400 meters BELOW sea level.
Answer:
I'm newbie here
Step-by-step explanation:
Elimination Method.
4x + 6/y = 15 → step 1
6x - 8/y = 14 → step 2
so,
4x + 6/y = 15 |×6|
6x - 8/y = 14 |×4|
24x + 6/y(6) = 90
24x - 8/y(4) = 56
24x + 36/y = 90
24x - 32/y = 56
____________ _
68/y = 34
68 = 34y
34y = 68
y = 2
subsitution y = 2 to..
4x + 6/y = 15
4x + 6/2 = 15
4x + 3 = 15
4x = 12
x = 3
So, for x is 3, and for y is 2
Can you take a picture of the problem?
