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sdas [7]
2 years ago
11

The function f is defined by the following rule. f(x) = x - 4 Complete the function table.

Mathematics
1 answer:
Vanyuwa [196]2 years ago
5 0

Answer:

-9

-6

-4

-3

0

Step-by-step explanation:

hope this helps!

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Use the table to find the relationship between the two quantities.
olchik [2.2K]

Answer:

the answer is 3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
ETHANHUNT HELP HERE WOULD BE APPRECIATED
labwork [276]
We know, Length of Image = Length of Object * Dilation factor, 

Just substitute your known values, 
Length of Image = 9 * 2 = 18

In short, Your Answer would be 18 cm

Hope this helps!
4 0
3 years ago
The video club to which Lin belongs allows her to receive one free DVD for every three DVDS she rents. If she pays $3 for each D
Nesterboy [21]

Answer:

12

Step-by-step explanation:

Given:

On every 3 DVDs she rents, 1 DVD is received for free

Rent of each DVD = $3

Total amount paid = $114

Now,

The total number of DVDs she took on rent = \frac{\textup{Total amount paid}}{\textup{Rent of each DVD}}

or

The total number of DVDs she took on rent = \frac{\textup{114}}{\textup{3}}

or

The total number of DVDs she took on rent = 38

also,

For every 3 DVDs she gets 1 Free DVD

thus,

For every 1 DVD she gets \frac{\textup{1}}{\textup{3}} free DVD

therefore,

For  38 DVD she gets \frac{\textup{38}}{\textup{3}} free DVD

or

she gets 12.67 DVDs free

Since,

the DVDs cannot be given in fraction

Hence she will get 12 free DVDs

5 0
3 years ago
The coordinates of the vertices of quadrilateral JKLM are J(-3,2), K(4,-1), L(2,-5) and M(-5,-2).
pashok25 [27]
<span>Slope of JK=((-1)-2)/(4-(-3)=-3/7 Slope of KL=((-5)-(-1)/(2-4=2 Slope of LM=((-2)-(-5))/(-5-2)=-3/7 Slope of MJ=(2-(-2))/((-3)-(-5))= 2 JK is parallel to LM and KL is parallel to MJ. Therefore JKLM is a parallelogram.</span>
5 0
3 years ago
Consider the differential equationy′′+3y′−10y=0.(a) Find the general solution to this differential equation.(b) Now solve the in
RSB [31]

Answer:

Y= 2e^(5t)

Step-by-step explanation:

Taking Laplace of the given differential equation:

s^2+3s-10=0

s^2+5s-2s-10=0

s(s+5)-2(s+5) =0

(s-2) (s+5) =0

s=2, s=-5

Hence, the general solution will be:

Y=Ae^(-2t)+ Be^(5t)………………………………(D)

Put t = 0 in equation (D)

Y (0) =A+B

2 =A+B……………………………………… (i)

Now take derivative of (D) with respect to "t", we get:

Y=-2Ae^(-2t)+5Be^(5t)   ....................... (E)

Put t = 0 in equation (E) we get:

Y’ (0) = -2A+5B

10  = -2A+5B ……………………………………(ii)

2(i) + (ii) =>

2A+2B=4 .....................(iii)

-2A+5B=10 .................(iv)

Solving (iii) and (iv)

7B=14

B=2

Now put B=2 in (i)

A=2-2

A=0

By putting the values of A and B in equation (D)

Y= 2e^(5t)

6 0
3 years ago
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