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kvasek [131]
3 years ago
12

What are the divisors of 64

Mathematics
1 answer:
Fed [463]3 years ago
5 0
The answer is 1, 2, 4, 8, 16, 32, and 64
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A is the answer.

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Multiply two and five-eighths negative two and three-fifths .
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on a recent hike through riverbend park antoinette traveled 2/3 mile in 1/3 hour . Which unit rate describes antoinettes speed i
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Answer:

Her speed is of 2 miles per hour.

Step-by-step explanation:

Velocity:

The velocity is given by the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance and t is the time.

2/3 mile in 1/3 hour .

This means that d = \frac{2}{3}, t = \frac{1}{3}

Which unit rate describes antoinettes speed in miles per hour?

This is v. So

v = \frac{d}{t} = \frac{\frac{2}{3}}{\frac{1}{3}} = \frac{2}{3}*\frac{3}{1} = 2

Her speed is of 2 miles per hour.

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2 years ago
A salad at the Millburn deli costs $4.95 plus $0.75 for each additional topping. You paid $9.45. How many toppings did you put o
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Read 2 more answers
Scores on a final exam taken by 1200 students have a bell shaped distribution with mean=72 and standard deviation=9
SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $ \pm $ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $ \frac{68}{100} \times 1200 $

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0
3 years ago
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