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nordsb [41]
3 years ago
9

Help! also please show work (and what letter it is A,B,C, or D).

Mathematics
1 answer:
frozen [14]3 years ago
8 0

Answer:

this angle is 90°.

5x°+55°=90°

5x=90°-55°

5x=35°

x=35/5

x=7

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Given cosα = −3/5, 180 < α < 270, and sinβ = 12/13, 90 < β < 180
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I got

-  \frac{6 3}{65}

What we know

cos a=-3/5.

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Angle A interval are between 180 and 270 or third quadrant

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What we need to find

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What we are going to apply

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\cos(a - b)  =  \cos(a)  \cos(b)  +  \sin(a)  \sin(b)

2. Use the interval it gave us.

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Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

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{12}^{2}  +  {y}^{2}  =  {13}^{2}

144 +  {y}^{2}  = 169

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Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

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( - 3) {}^{2}  +  {x}^{2}  =  {5}^{2}

9 +  {x}^{2}  = 25

{x}^{2}  = 16

x = 4

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

-  \frac{3}{5}  \times  \frac{5}{13}  +   - \frac {4}{5}  \times  \frac{12}{13}

- \frac{15}{65} + (  - \frac{48}{65}  )

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Hope this helps

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