Express each number in standard form<br> -9.5x10-3<br> This is 10 to the -3 power

How do I do long division step by step

murzikaleks [220]

Yo can download the App photomath and it shows you how to divide step by step long numbers

6 0

4 years ago

Which table shows a function that is decreasing only over the interval (-1, ")?

3241004551 [841]

The answer is x bc when you decreasing the interval f(x) it will equal (-2)

7 0

3 years ago

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A computer downloads files at a constant rate. The table shows how many megabytes the computer downloads over specific lengths o

Dennis_Churaev [7]

The problem ask to calculate the slope of the line base on the diagram or table you give. To calculate the slope you must first know its formula and that is Rise/Run and also be Y/X so you must divide the Megabytes and the Minute and with that calculation the slope is 3.75 so the equation will be y=3.75x

5 0

4 years ago

Which of these choices show a pair if equivelent expressions? Chack all that apply

Gwar [14]

Answer:

A. $(\sqrt[3]{125})^9\ and\ (125)^{\frac{9}{3}}$

D. $8^{\frac{9}{2}}\ and\ (\sqrt{8})^9$

Step-by-step explanation:

Equivalent expressions are those expressions that simplify to same form.

Now, let us check each of the given options.

Option A:

$(\sqrt[3]{125})^9\ and\ (125)^{\frac{9}{3}}$

We know that,

$\sqrt[n]{x} =x^{\frac{1}{n}}$

Therefore, $\sqrt[3]{125} =(125)^{\frac{1}{3}}$

Thus the first expression becomes;

$((125)^{\frac{1}{3}})^9$

Now, using law of indices $(a^m)^n=a^{m\times n}$ , we get

$((125)^{\frac{1}{3}})^9=((125))^{\frac{1}{3}\times 9}=((125))^{\frac{9}{3}$

Therefore, $(\sqrt[3]{125})^9\ and\ (125)^{\frac{9}{3}}$ are equivalent.

Option B:

$12^{\frac{2}{7}}\ and\ (\sqrt{12})^7$

Consider the second expression $(\sqrt{12})^7$

We know that,

$\sqrt x=x^{\frac{1}{2}}$

$(\sqrt{12})^7=((12)^{\frac{1}{2}})^7=(12)^{\frac{1}{2}\times 7}=(12)^{\frac{7}{2}}$

Therefore, $12^{\frac{2}{7}} \ne (12)^{\frac{7}{2}}$ . Hence, the expressions $12^{\frac{2}{7}}\ and\ (\sqrt{12})^7$ are not equivalent.

Option C:

$4^{\frac{1}{5}}\ and\ (\sqrt 4)^5$

We know that,

$x^{\frac{1}{n}}=\sqrt[n]{x}$

Therefore, $4^{\frac{1}{5}}=\sqrt[5]{4}$

Now, $\sqrt[5]{4}\ne (\sqrt 4)^5$

Therefore, the expressions $4^{\frac{1}{5}}\ and\ (\sqrt 4)^5$ are not equivalent.

Option D:

$8^{\frac{9}{2} }\ and\ (\sqrt 8)^9$

Using law of indices $a^{m\times n}=(a^m)^n$ , we get

$8^{\frac{9}{2} }=(8^{\frac{1}{2}})^9$

Now, we know that, $x^{\frac{1}{2}}=\sqrt x$

So, $(8^{\frac{1}{2}})^9=(\sqrt8)^9$

Therefore, $8^{\frac{9}{2} }\ and\ (\sqrt 8)^9$ are equivalent.

8 0

3 years ago

Find the area of the semicircle. Round your answer to the nearest hundredth.

Neporo4naja [7]

Answer:

56.52

Step-by-step explanation:

This is because in order to find an area of a circle you must do R^2*3.14 and since it is a semicircle add /2 so R^2*3.14/2 and since half of 12 is 6, 6*6 is 36 and 36*3.14 is 113.04 and divide that by 2 which is 56.52

4 0

3 years ago

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Express each number in standard form -9.5x10-3 This is 10 to the -3 power