Which proportions show that the triangles are not similar?
1 answer:
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The picture in the attached figure
we know that
RX+RA+XA=24
XA=24-RA-RX------> XA=24-11-4----> XA=9
XA=XP+PA
so
XP+PA=9------> XP=9-PA-----> equation 1
RX/XP=RA/PA
11*XP=4*PA-----> equation 2
substitute equation 1 in equation 2
11*[9-PA]=4*PA-----> 99-11*PA=4*PA----> 15*PA=99----> PA=99/15
PA=6.6
XP=9-PA-----> XP=9-6.6----> XP=2.4
the answer is the option
<span>B. XP = 2.4, PA = 6.6 </span>
we know that
RX+RA+XA=24
XA=24-RA-RX------> XA=24-11-4----> XA=9
XA=XP+PA
so
XP+PA=9------> XP=9-PA-----> equation 1
RX/XP=RA/PA
11*XP=4*PA-----> equation 2
substitute equation 1 in equation 2
11*[9-PA]=4*PA-----> 99-11*PA=4*PA----> 15*PA=99----> PA=99/15
PA=6.6
XP=9-PA-----> XP=9-6.6----> XP=2.4
the answer is the option
<span>B. XP = 2.4, PA = 6.6 </span>