If the total area of a picture measuring 10 inches by 12 inches plus a matting of uniform width surrounding the picture is 224 s
quare inches, the width of the matting is
A: 2 inches
B: 2 4/11 inches
C: 3 inches
D: 4 inches
A: 2 inches
B: 2 4/11 inches
C: 3 inches
D: 4 inches
1 answer:
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Answer: x = 11
Work Shown:
Hello there!
Part A: Solve for n; -n*p - 90 < 30
Add 90 to both sides.
-n*p < 120
Divide both sides by p.
-n < 120/p
Divide both sides by -1.
n
120/-p is your answer for part A.
Part B: Solve for h; 5m - 3h = 45
Subtract 5m from both sides.
-3h = -5m + 45
Divide both sides by -3.
h = (-5m + 45)/-3 is your answer for part B.
I hope this helps!
Part A: Solve for n; -n*p - 90 < 30
Add 90 to both sides.
-n*p < 120
Divide both sides by p.
-n < 120/p
Divide both sides by -1.
n
Part B: Solve for h; 5m - 3h = 45
Subtract 5m from both sides.
-3h = -5m + 45
Divide both sides by -3.
h = (-5m + 45)/-3 is your answer for part B.
I hope this helps!