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marishachu [46]
3 years ago
7

A soda can has a diameter of 2.5 inches and is 4.8 inches tallFind the surface area of the soda can. Round to the nearest hundre

dth.
Mathematics
1 answer:
Andre45 [30]3 years ago
5 0

Answer:

a soda can has diameter 2.5 and 4.8 find surface is divides by 1.98

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Find the sum of the following infinite geometric series, if it exists. 2 + 6 + 18 + 54 +… Does not exist 23,567 25,982 29,034
Sladkaya [172]

Option A: The sum for the infinite geometric series does not exist

Explanation:

The given series is 2+6+18+54+.......

We need to determine the sum for the infinite geometric series.

<u>Common ratio:</u>

The common difference for the given infinite series is given by

r=\frac{6}{2}=3

Thus, the common difference is r=3

<u>Sum of the infinite series:</u>

The sum of the infinite series can be determined using the formula,

S_{\infty}=\frac{a}{1-r}   where 0

Since, the value of r is 3 and the value of r does not lie in the limit 0

Hence, the sum for the given infinite geometric series does not exist.

Therefore, Option A is the correct answer.

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Answer:

0,-3

Step-by-step explanation:

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Find the Answer to <br><br><br>y = [???]
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Y=60°

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Write an equation in Standard Form. A store sells t-shirts for $12 each and
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Standard form: Ax + By = C
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Someone please help.
Alexxandr [17]

Hi there!

f(x)+f(x+1)=4f(x)

There are 3 parts to this equation:

f(x)

f(x+1)

4f(x)

We must first determine these three parts separately.

<u>1) f(x)</u>

We're given that  f(x)=3^x:

⇒ f(x)=3^x:

<u>2) f(x+1)</u>

Now, we must find f(x+1). To do so, add 1 to x in the original function f(x)=3^x:

⇒ f(x+1)=3^x^+^1

<u>3) 4f(x)</u>

To find 4f(x), multiply the original function f(x)=3^x by 4:

4f(x)=4*3^x:

<u>4) Put it all together</u>

Now, plug each of the three parts into the equation f(x)+f(x+1)=4f(x):

f(x)+f(x+1)=4f(x)

3^x+3^x^+^1=4*3^x\\3^x+3^x*3=4*3^x

Factor the left side

3^x*(1+3)=4*3^x

Divide both sides by 3^x

1+3=4\\4=4

Because this equation is true, f(x)+f(x+1)=4f(x) is therefore true.

I hope this helps!

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