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Aleks04 [339]
2 years ago
14

the boiling point of water is 212•F. the boiling point of helium is -452•F. how would you compare the temperatures using an ineq

uality?
Mathematics
2 answers:
Rom4ik [11]2 years ago
7 0

Answer:

-452•F < 212•F.

Step-by-step explanation:

Given : the boiling point of water is 212•F. the boiling point of helium is -452•F.

To find :  how would you compare the temperatures using an inequality.

Solution : We have given

Boiling point of water =  212•F.

Boiling point of helium =  -452•F.

We know that negative value is always less than positive value.

So, we will use the inequality

Boiling point of helium is less than Boiling point of water.

-452•F < 212•F.

Therefore,  -452•F < 212•F.

Luden [163]2 years ago
6 0

-452°F < 212°F

A negative number is always less than a positive number.

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A school will offer pizza on Friday's if at least 30% of the students will buy it. A sample of 50 students asked if they would b
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Answer:

0.0614

Step-by-step explanation:

Solution:-

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- We will denote a random variable X: the number of students willing to buy Pizza on fridays.

- For the sample of n = 50, for Pizza to be offered on friday the expected number of student who should opt for buying must be at-least:

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- The standard deviation for the normal distribution can be determined as follows:

          standard deviation ( s ) = √n*p*(1-p)

                                                 = √50*0.3*(0.7)

                                                 = √10.5 = 3.2404

- We will assume that the random variable X follows normal distribution:

                       X ~ Norm ( 15 , 3.2404^2 )

- To determine the probability of sample of size n = 50 with proportion or lower. The number of people willing to buy pizza on friday as per survey are x = 10.

- Evaluate the standard normal ( Z-score ):

                      P ( X < x ) = P ( Z < ( x - u ) / s )

                      P ( X < 10 ) = P ( Z < ( 10 - 15 ) / 3.2404 )

                      P ( X < 10 ) = P ( Z < -1.54301 )

- Use the standard normal tables to determine the value of P ( Z < -1.54301 ):

                     P ( X < 10 ) = P ( Z < -1.54301 ) = 0.0614

Answer: The probability of getting a sample with the proportion or lower given a population with a proportion of .30 is 0.0614.

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