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2 years ago

If the factors of a quadratic function are (x + 2) and (x − 9), what are the x-intercepts of the function?

Mathematics

1 answer:

Zielflug [23.3K]2 years ago

8 0

Answer: D. (-2,0) and (9,0)

Step-by-step explanation:

When you equate the factors to 0 you get

(X+2) = 0

X = -2

(X-9) = 0

X= 9

Here the Y value is 0 as you find the factors of x when the Y value is 0.

So the answer is (-2,0) and (9,0)

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Answer:

Part 1) $FG=4.4\ units$

Part 2) $EF=3.9\ units$

Part 3) $m\angle G=63^o$

Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

we know that

$sin(27^o)=\frac{GE}{FG}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(27^o)=\frac{2}{FG}$

$FG=\frac{2}{sin(27^o)}=4.4\ units$

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

$cos(27^o)=\frac{EF}{FG}$ ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

$cos(27^o)=\frac{EF}{4.4}$

$EF=cos(27^o)(4.4)=3.9\ units$

step 3

Find the measure of angle G

we know that

$m\angle G+27^o=90^o$ ---> by complementary angles in a right triangle

$m\angle G=90^o-27^o=63^o$

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