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grin007 [14]
3 years ago
13

The square root of 52 is between which two consecutive intergers?

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
7 0

Answer: b) 7 and 8

Step-by-step explanation:

The formula for calculating the square root of non perfect square is given as :

square root of non perfect square = square root of the nearest lower perfect square + (difference between the number and the perfect square)/ 2x the perfect square.

To find the square root of 52.

The nearest lower perfect square to 52 is 49 , applying the formula , we have:

\sqrt{52} = \sqrt{49} - \frac{52-49}{2\sqrt{49}}

\sqrt{52} = 7 + \frac{3}{2(7)}

\sqrt{52} = 7 + \frac{3}{14}

This shows clearly that \sqrt{52} is between the integer 7 and 8

Tanya [424]3 years ago
4 0

Answer: 7 and 8

Step-by-step explanation:

The square root of 7 is 49 and the square root of 8 is 64

52 is in between the 2 consecutive integers 7 and 8

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Oduvanchick [21]

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Option c is correct answer

Step-by-step explanation:

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3 years ago
What is the answer to 5 - a0 = 14
nikklg [1K]

Answer:

There are no solutions.

Step-by-step explanation:

cuz they ain't all real numbers

im wrong

5 0
3 years ago
A kite was broken into two triangles. PLEASE HELP ASAP ​
kumpel [21]

Answer:

ok

Step-by-step explanation:

6 0
3 years ago
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Solve this please!! I'm really stuck
lora16 [44]

Answer:

-74.

Step-by-step explanation:

First, notice that we can divide it into 2 equations (1 on each side of the equal symbol).

<h3>1st step:</h3>

Replace where's x by -2 in the left equation:

x+\:-4+\:-2(3x-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:replace\:x\:by\:-2}\\-2+\:-4+\:-2((3\cdot-2)-5)=\square\mathrm{\:\:\:\:solve\:the\:multiplication}\\-2-4-2(-6-5)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:remove\:excess\:symbols}\\-2-4-2(-11)=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:multiplication}\\-2-4+22=\square\mathrm{\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:solve\:subtraction}\\16=\square

<h3>2nd step:</h3>

Now, we will replace the squares with 16 in the second equation. Look:

\square +-4+-2(3\cdot\square\cdot-5)=\triangle\\16 +-4+-2(3\cdot16-5)\\16-4-2(48-5)\\16-4-2(43)\\16-4-86\\=-74

So, the answer is -74.

<h2>We also can solve it in another way:</h2>

x-4-2(3x-5)=\\x-4-6x+10\\-5x+6\\\\\mathrm{let's\:replace\:x\:by\:-2:}\\-5\cdot(-2)+6\\10+6\\=16

Now let's call the gray square as y in the second equation:

y-4-2(3y-5)\\y-4-6y+10\\-5y+6\\\\\mathrm{let's\:replace\:y\:by\:16:}\\-5\cdot(16)+6\\-80+6\\=-74

So, your final answer is -74.

Hope it helps! :D

7 0
2 years ago
What is 10-10×10+10=
Dmitry [639]
10-10•10+10=-80
The answer would be negative eighty
4 0
3 years ago
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