Answer:
Step-by-step explanation: I choose d because if you notice there are only 33 marbles in Bag F and Bag F-number of marbles is equal to 1/3 marbles = 11/33 marbles and Bag G contains only 11 marbles which are how many marbles there are in all bags.
Answer:
see explanation
Step-by-step explanation:
Using De Moivre's theorem
Given
[ 4(cos15° + isin15° ) ]³, then
= 4³ [ cos(3 × 15°) + isin(3 × 15°) ]
= 64 (cos45° + isin45° )
= 64 (
+
i )
= 64 (
(1 + i) )
= 32
(1 + i)
= 32
+ 32
i
80 would be your answer for this question
This question not incomplete
Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
f = (1/2)(m), for m = 1
f = (1/2)(1)
Step-by-step explanation: