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4 years ago

6

Find the equation of the line passing through the given points (-5,6) and (-5,8)

1 answer:

diamong [38]4 years ago

8 0

Answer:

x = -5

Step-by-step explanation:

To find the equation of a line, use the formula y = mx + b, where m is the slope of the line and b is the y intercept.

To find the slope, use your ordered pairs: m = (y2 - y1)/(x2 - x1). Substituting in your values, m = (8-6)/(-5 - -5), or m = 2/0. Since you cannot divide by 0, the slope is undefined; you have a vertical line.

If you plot the points on a graph, (-5, 6) and (-5, 8) both pass through -5 on the x axis. Since this is a vertical line, it will never cross the y axis, so you will not have a y intercept.

Your equation is x = -5.

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Consider this right triangle.<br> 21<br> 29<br> 20<br> Enter the ratio equivalent to s

AleksAgata [21]

Answer:

Part 1) $sin(B)=\frac{21}{29}$

Part 2) $csc(A)=\frac{29}{20}$

Part 3) $cot(A)=\frac{21}{20}$

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

$sin(B)=\frac{AC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(B)=\frac{21}{29}$

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

$csc(A)=\frac{1}{sin(A)}$

$sin(A)=\frac{BC}{AB}$ -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(A)=\frac{20}{29}$

therefore

$csc(A)=\frac{29}{20}$

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

$cot(A)=\frac{1}{tan(A)}$

$tan(A)=\frac{BC}{AC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{20}{21}$

therefore

$cot(A)=\frac{21}{20}$

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