Answer:
1. Do rise, over run
2. y2-y1 / x2-x1
Step-by-step explanation:
Step-by-step explanation:
initial speed = 272 ft/s
h = -16t² + 272t
a. 1120 = -16t² + 272t we change a bit into
16t² - 272t + 1120 = 0 then divide all with factor 16
t² - 17t + 70 = 0
(t - 10)(t - 7) = 0
t = 10 and t = 7
7 s when it goes up and 10 sec when the rocket goes down.
b. 1152 = -16t² + 272t we change a bit into
16t² - 272t + 1152 = 0 then divide all with factor 16
t² - 17t + 72 = 0
(t - 9)(t - 8) = 0
t = 9 and t = 8 sec
c. since the answer of a and b is:
7 sec and 8 sec the rocket goes up but at 9 sec and 10 sec the rocket goes down then we can take conclusion that the maximum height is reached at 8.5 s
so how long the rocket in the air?
goes up : 8.5 sec
goes down : 8.5 sec
total = 17 sec
<h2>
Hello!</h2>
The answers are:
<h2>
Why?</h2>
Since we are given the margin of error and it's equal to ±0.1 feet, and we know the surveyed distance, we can calculate the maximum and minimum distance. We must remember that margin of errors usually involves and maximum and minimum margin of a measure, and it means that the real measure will not be greater or less than the values located at the margins.
We know that the surveyed distance is 1200 feet with a margin of error of ±0.1 feet, so, we can calculate the maximum and minimum distances that the reader could assume in the following way:
Have a nice day!
1)find the area of a triangle. Multiply it by 2 or 4 depending on if they are the same size
2)find the area of the base
3)find the area of the other two sides if you haven’t already.
4) add them all together
<span>8d3 + (6d2 – 4d)
=</span><span>8d3 + 6d2 – 4d
=2d(4d^2 + 3d - 2)
=2d(2d - 1)(d + 2) ...simplify and this is your answer
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