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dimulka [17.4K]
3 years ago
7

Find the value of x and. Will mark brainliest.

Mathematics
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

x=5

y=25

Step-by-step explanation:

You can start by finding the value of x. Since opposite angles in a parallelogram are equal, 11x=55 and x=5. Since adjacent angles are supplementary, 5y+55=180, 5y=125 and y=25. Hope this helps!

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A company is going to make a water tank in the shape of a cylinder. As shown below, the tank will have a height of 4ft and a rad
AleksAgata [21]

First find surface area.

I will skip the exact explanation and just go to it because well its the same concept as the prism.

π*6^2*2+6*2π*4

=72π+48π

=120π

Now we need to take 3.14 for pi getting about

120*3.14=376.8 square foot.

Now the total is 14318.4 dollars, so what's left is simple division.

14318.4/376.8=38

The metal cost 38 dollars per square feet :P

4 0
3 years ago
What is weathering and features formed through weathering​
DochEvi [55]

Answer:Weathering describes the breaking down or dissolving of rocks and minerals on the surface of the Earth. Water, ice, acids, salts, plants, animals, and changes in temperature are all agents of weathering. Once a rock has been broken down, a process called erosion transports the bits of rock and mineral away.

Step-by-step explanation:

6 0
3 years ago
In right ABC, AN is the altitude to the hypotenuse. FindBN, AN, and AC,if AB =2 5 in, and NC= 1 in.
Rama09 [41]

From the statement of the problem, we have:

• a right triangle △ABC,

,

• the altitude to the hypotenuse is denoted AN,

,

• AB = 2√5 in,

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• NC = 1 in.

Using the data above, we draw the following diagram:

We must compute BN, AN and AC.

To solve this problem, we will use Pitagoras Theorem, which states that:

h^2=a^2+b^2\text{.}

Where h is the hypotenuse, a and b the sides of a right triangle.

(I) From the picture, we see that we have two sub right triangles:

1) △ANC with sides:

• h = AC,

,

• a = ,NC = 1,,

,

• b = NA.

2) △ANB with sides:

• h = ,AB = 2√5,,

,

• a = BN,

,

• b = NA,

Replacing the data of the triangles in Pitagoras, Theorem, we get the following equations:

\begin{cases}AC^2=1^2+NA^2, \\ (2\sqrt[]{5})^2=BN^2+NA^2\text{.}\end{cases}\Rightarrow\begin{cases}NA^2=AC^2-1, \\ NA^2=20-BN^2\text{.}\end{cases}

Equalling the last two equations, we have:

\begin{gathered} AC^2-1=20-BN^2.^{} \\ AC^2=21-BN^2\text{.} \end{gathered}

(II) To find the values of AC and BN we need another equation. We find that equation applying the Pigatoras Theorem to the sides of the bigger right triangle:

3) △ABC has sides:

• h = BC = ,BN + 1,,

,

• a = AC,

,

• b = ,AB = 2√5,,

Replacing these data in Pitagoras Theorem, we have:

\begin{gathered} \mleft(BN+1\mright)^2=(2\sqrt[]{5})^2+AC^2 \\ (BN+1)^2=20+AC^2, \\ AC^2=(BN+1)^2-20. \end{gathered}

Equalling the last equation to the one from (I), we have:

\begin{gathered} 21-BN^2=(BN+1)^2-20, \\ 21-BN^2=BN^2+2BN+1-20 \\ 2BN^2+2BN-40=0, \\ BN^2+BN-20=0. \end{gathered}

(III) Solving for BN the last quadratic equation, we get two values:

\begin{gathered} BN=4, \\ BN=-5. \end{gathered}

Because BN is a length, we must discard the negative value. So we have:

BN=4.

Replacing this value in the equation for AC, we get:

\begin{gathered} AC^2=21-4^2, \\ AC^2=5, \\ AC=\sqrt[]{5}. \end{gathered}

Finally, replacing the value of AC in the equation of NA, we get:

\begin{gathered} NA^2=(\sqrt[]{5})^2-1, \\ NA^2=5-1, \\ NA=\sqrt[]{4}, \\ AN=NA=2. \end{gathered}

Answers

The lengths of the sides are:

• BN = 4 in,

,

• AN = 2 in,

,

• AC = √5 in.

7 0
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kati45 [8]

Answer:

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7 0
3 years ago
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Zarrin [17]
Ok, so what we want to do here is first remove the repeating decimal.

x=2.16 repeating
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Subtract 10x=21.6 repeating from 100x=216.6 repeating. This will get rid of the repeating numbers.

100x=216.6 repeating
-10x=21.6 repeating
__________________
90x=195

Divide both sides by 90.

x=195/90

Now you can simplify that into 13/6.


5 0
3 years ago
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