1. Answer (D). By the law of sines, we have 
in any 
2. Answer (C). The law of cosines, 
accepts up to three sides and an angle as an input.
3. Answer (D). Although this triangle is right, we are not given enough information to uniquely determine its sides and angles - here, we need either one more side or one more angle.
4. Answer (D). Don't get tripped up by answer choice (C) - this is just a rearrangement of the statement of the law of cosines. In choice (D), the signs of 
and 
are reversed.
5. Answer (B). By the law of sines, we have 
Solving gives 
Note that this is the <em>ambiguous (SSA) case</em> of the law of sines, where the given measures could specify one triangle, two triangles, or none at all!
6. Answer (A). Since we know all three sides and none of the angles, starting with the law of sines will not help, so we begin with the law of cosines to find one angle; from there, we can use the law of sines to find the remaining angles.
The equation of the parent square root function to represent the equation of the graphed function will be, y=√x-2
According to the statement
we have to show the square root function as a equation in the graphical representation.
So,
we know that the definition of a
Graph a diagram showing the relation between variable quantities, typically of two variables and it also show the relation between more than two variables.
Now, we know that the definition of Equation is a mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.
And the equation obtained from the graph is a y=√x-2 by a some calculations in the graph.
So, The equation of the parent square root function to represent the equation of the graphed function will be, y=√x-2
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Answer:
7y + 14
Step-by-step explanation:
7(y+2) = 7y + 14
I think the equation is y= -1/3x+1. The slope is going down, so it’s negative. And the y intercept is 1. And how I got a fraction is by using rise/run.
Candidates range from 1 to 50.
50/4=12 positive integers are multiples of 4
50/6=8 positive integers are multiples of 6
50/12=4 positive integers are multiples of 12 (LCM of 4 and 6)
By the inclusion/exclusion principle, the number of multiples of either 4 or 6 is equal to 12+8-4=16.
Therefore, the complement is the number of positive integers that are multiples of neither 4 nor 6 = 50-16=34.
