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3 years ago

Hell me plz, and can plz explain as well

Mathematics

1 answer:

Montano1993 [528]3 years ago

7 0

The sixth graders collected $250 of their $300 goal. The seventh graders collected $250 of thier $450 goal.

Sixth Graders:
$250 / $300
Reduce: $25 / $30 = 5/6

Seventh Graders:
$250 / $450
Reduce: $25 / $45 = 5/9

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How to find the value of f(-3)

Evgesh-ka [11]

Answer:

plug in -3 where any x is in the equation. I reccomend doing it in parenthesis just so things work out nicely

Step-by-step explanation:

$x^2-x^3\\(-3)^2-(-3)^3\\(-3*-3)-(-3*-3*-3)\\(9)-(-27)\\9+27\\36$

3 0

3 years ago

Read 2 more answers

Three subtracted from 5 x a number is -128. what is that number

omeli [17]

5-3x=-128

LHS = RHS

(5 - 3) x A = -128

( 2 ) x A = -128

2A / 2 = -128 / 2

A = -64

3 0

3 years ago

slava [35]

Answer:

Equation 1 x=-16

Equation 2 m=-3

Step-by-step explanation:

Equation 1

3x-x=-24-6

2x=-32

x=-32/2

x=-16

Equation 2

-2m=16-10

-2m=6

m=6/-2

m=-3

6 0

3 years ago

3. The adult men of the Dinaric Alps have the highest average height of all regions. The

ahrayia [7]

Using the normal distribution, it is found that:

3 - a) The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

3 - b) The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

4 - a) The 25th percentile for the math scores was of 71.6 inches.

4 - b) The 75th percentile for the math scores was of 78.4 inches.

<h3>Normal Probability Distribution </h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

Question 3:

The mean is of 73 inches, hence $\mu = 73$ .

The standard deviation is of 3 inches, hence $\sigma = 3$ .

Item a:

The 40th percentile is X when Z has a p-value of 0.4, so X when Z = -0.253.

$Z = \frac{X - \mu}{\sigma}$

$-0.253 = \frac{X - 73}{3}$

$X - 73 = -0.253(3)$

$X = 72.2$

The 40th percentile of the height of Dinaric Alps distribution for men is of 72.2 inches.

Item b:

The minimum height is the 100 - 10 = 90th percentile is X when Z has a p-value of 0.9, so X when Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 73}{3}$

$X - 73 = 1.28(3)$

$X = 76.84$

The minimum height of man in the Dinaric Alps that would place him in the top 10% of all heights is of 76.84 inches.

Question 4:

The mean score is of 75, hence $\mu = 75$ .

The standard deviation is of 5, hence $\sigma = 5$ .

Item a:

The 25th percentile is X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 75}{5}$

$X - 75 = -0.675(5)$

$X = 71.6$

The 25th percentile for the math scores was of 71.6 inches.

Item b:

The 75th percentile is X when Z has a p-value of 0.25, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 75}{5}$

$X - 75 = 0.675(5)$

$X = 78.4$

The 75th percentile for the math scores was of 78.4 inches.

To learn more about the normal distribution, you can take a look at brainly.com/question/24663213

5 0

2 years ago

Which of the following statements about the number line is true?

rusak2 [61]

It is D i think.............
.

8 0

3 years ago

Read 2 more answers