What is the vertex of the function f(x) = x2 + 12x?
2 answers:
Answer:
6, - 36 )
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = -
f(x) = x² + 12x ← is in standard form
with a = 1, b = 12, c = 0 , then
x = - = - 6
Substitute x = 6 into f(x) for corresponding value of y
f(6) = 6² + 12(- 6) = 36 - 72 = - 36
vertex = (6, - 36 )
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First step, divide 6 from both sides.
t/6=r^2+1
second step, subtract 1 from both sides
t/6 -1=r^2
Now take the square root of each side.
Done!