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s2008m [1.1K]
3 years ago
13

What is the vertex of the function f(x) = x2 + 12x?

Mathematics
2 answers:
Volgvan3 years ago
8 0

Answer:

A: (-6, -36)

Step-by-step explanation:

This should be the right answer on edge,

please correct me if I'm wrong.

saul85 [17]3 years ago
5 0

Answer:

6, - 36 )

Step-by-step explanation:

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

f(x) = x² + 12x ← is in standard form

with a = 1, b = 12, c = 0 , then

x = - \frac{12}{2} = - 6

Substitute x = 6 into f(x) for corresponding value of y

f(6) = 6² + 12(- 6) = 36 - 72 = - 36

vertex = (6, - 36 )

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F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
2 years ago
A boat is traveling at a constant speed. In 10 hours, the boat travels 160 miles. How many hours will it take the boat to travel
Novay_Z [31]
1 hour, 32 min, HAHAHA not sure.
4 0
3 years ago
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5z3 - 224 - 9z2 + 2<br> What is the degree of the polynomial?<br> I
hoa [83]

Answer:

5{z}^{3}-222-9{z}^{2}5z

​3

​​ −222−9z

​2

Step-by-step explanation:

1 Collect like terms.

5{z}^{3}+(-224+2)-9{z}^{2}5z

​3

​​ +(−224+2)−9z

​2

​​  

2 Simplify.

5{z}^{3}-222-9{z}^{2}5z

​3

​​ −222−9z

​2

​​  

Done

7 0
3 years ago
Judd is 3 years older than Jordan. Jordan is 6 years younger than Chris. Write an algebraic expression for the sum of their ages
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Answer:

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6 0
2 years ago
solve the system of equations below by graphing both equations with a pencil and paper what is the solution y=2x-4 y=-x+5
miss Akunina [59]

Answer:

The coordinate of the points on the graph as shown , where                  ( x ,y ) = ( 3 , 2 )

Step-by-step explanation:

Given as :

The two algebraic equation is

y = 2 x - 4   .......A     and  y = - x + 5         ........B

The given two algebraic equation can be solved by putting the one variable to the other equation

Now , put the value of y  from Eq A into the Eq B

I.e 2 x - 4 = - x + 5

or, 2 x + x = 5 + 4

or, 3 x = 9

∴  x = \frac{9}{3}

I.e x = 3

So The value of x = 3

Again,  put the value of x in the equation A

I.e y = 2 x - 4

or, y = 2 × 3 - 4

∴  y = 6 - 4

I.e y = 2

So The value of y = 2

So , The coordinate of points on the graph as ( x , y ) = ( 3 , 2 )

Hence The coordinate of the points on the graph as shown , where               ( x ,y ) = ( 3 , 2 )  Answer

6 0
3 years ago
Read 2 more answers
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