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makkiz [27]
3 years ago
5

Explain how you got 43+58+62+57+42=262

Mathematics
1 answer:
aev [14]3 years ago
6 0

Answer:

If you take All of them and add them then you get 262 I dont really understand what your trying to say

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Solve for x <br>81^5 = 3x<br>x=?<br>​
pentagon [3]
81^5 = 3,486,784,401
3,486,784,401 / = X
X = 1,162,261,467
(I think anyways)
8 0
3 years ago
Explain how to find the sum −8.46+5.31. a.) Because |−8.46|&gt;|5.31|, subtract |5.31| from |−8.46| and the sign is negative. b.
Amanda [17]

Step-by-step explanation:

Sum of −8.46 and 5.31 means we need to add −8.46+5.31.

We know that,

|-8.46| > |5.31|

It means we subtract 8.46 - 5.31

At hundredth place, 6-1 = 5

At tenths place, 4-3 = 1

At ones place, 8-5 = 3

It would mean that, 8.46 - 5.31 = 3.15

8.46 has a negative sign. It means that the final answer will have negative sign i.e. −8.46+5.31 = -3.15

Hence, the correct option is (a) " Because |−8.46|>|5.31|, subtract |5.31| from |−8.46| and the sign is negative".

5 0
3 years ago
The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu
m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. \mu=23.50

\sigma=5

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let \overline{x} be the sample mean.

Formula : z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

Then, the probability that the sample mean is at least $25.00 will be :-

P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0
4 years ago
This list shows the age at which 43 U.S. Presidents began their terms.
Artist 52 [7]

The best intervals would be 41-45, 46-50, 51-55, 56-60, 61-65, and 69-70.

The best way to decide the appropriate interval would be to find the range of the numbers.

We have given a data set,

<h3>What is the smallest value in the data?</h3>

The minimum is the smallest value in the data set. The maximum is the largest value in the data set.

<h3>What is the largest minus the smallest? </h3>

This would be 69-42=27.

If you need six intervals you would need to round 27 up to 30 to be able to divide it out evenly and include all of the data.

The best intervals would be 41-45, 46-50, 51-55, 56-60, 61-65, and 69-70.

This way you are one over and one under the highest and lowest values.

Therefore, The best intervals would be 41-45, 46-50, 51-55, 56-60, 61-65, and 69-70.

To learn more about the interval visit:

brainly.com/question/12221823

#SPJ1

4 0
2 years ago
Help quick!.................
LUCKY_DIMON [66]

Answer: D.

Step-by-step explanation:

I think its d because there all equally apart and proportionate

8 0
3 years ago
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