Question

Four times the sum of a number and -3 is 4 more than times the number. Write and solve and equation to find the number.

Answer 1

The number is $x = \frac{16}{3}$.

Explanation:

We have , Four times the sum of a number and -3 is 4 more than times the number.Let's consider step by step as :

Let the number be x , Four times sum of a number & -3 is $4 ( x - 3 )$. Now, this is 4 more than times the number i.e $x + 4$. According to question these both statements are equivalent as :

⇒$4(x - 3 ) = x + 4$

⇒ $4x - 12 = x + 4$

⇒ $3x = 16$

⇒$x = \frac{16}{3}$

Answer 2

Answer:

The number is $\frac{16}{3}$ .

Explanation:

Let the number be denoted by x.

Now the sum of number and -3 is : (x-3)

Four times this sum is : 4(x-3)

The number that is 4 more than x is : 4+x

Represent these data in equation we get;

                                     4(x-3)= 4+x

                                or, 4x - 12 = 4 + x

                                or, 4x-x= 12 +4

                                or, 3x = 16

                                or, x= $\frac{16}{3}$

Hence the required number is  $\frac{16}{3}$ .