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3 years ago

7

I need help ! 1-2x+5=4x-3

2 answers:

Rus_ich [418]3 years ago

6 0

$\huge\boxed{x=\frac{3}{2}}$

We need to isolate $x$ .

$1-2x+5=4x-3$

Rearrange the terms a little bit. $-2x+1+5=4x-3$

Add the like terms. $-2x+6=4x-3$

Subtract $4x$ from both sides. $-2x-4x+6=-3$

Subtract $6$ from both sides. $-2x-4x=-3-6$

Combine the like terms. $-6x=-9$

Divide both sides by $-6$ . $x=\frac{-9}{-6}$

Simplify. $x=\boxed{\frac{3}{2}}$

hram777 [196]3 years ago

3 0

1-2x+5=4x-3

1+5-2x=4x-3

6-2x=4x-3

Move 6 to the other side

Sign changes from +6 to -6

6-6-2x=4x-3-6

-2x=4x-9

Move 4x to the other side

Sign changes from +4x to -4x

-2x-4x=4x-4x-9

-2x-4x=-9

-6x=-9

Divide both sides by -6

-6/-6=-9/-6

x=9/6

reduce the fraction by dividing by 3

9/3=3

6/3=2

Answer: x=3/2 or x=1 1/2

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Which expression converts 100 inches per minute to feet per minute?

sukhopar [10]

Answer:

100 inches Over 1 minute times × 1 foot Over 12 inches

Step by Step explanation

Remember that

1ft=12in

4 0

3 years ago

HELP IMMEDIATELY! Please help, on 1, 2 and 3. I’m so lost :(

Nesterboy [21]

When two variables are proportionate, they increase and decrease at the same ratio.

36 / 40 = 0.9

0.9 * 140 = 126

When y = 140, x = 126.

2. 150 / 30 = 5

5 * 48 = 240lbs

A person who weighs 48 lbs on the moon weighs 240lbs on Earth.

3. 110 / 66 = 0.6

0.6 * 80 = 48

y = 48 when x = 80

4 0

4 years ago

A photograph measures 4 inches wide and 5 inches long if you have the photograph in large to fit a frame 36 inches long what is

Margarita [4]

The correct answer is A

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3 years ago

determine if the sequence is geometric if it is find the common ratio the 8th term and the explicit formula can someone check my

mylen [45]

Answer:

You can check the answer by yourself after seeing the below answer.

Step-by-step explanation:

A sequence is geometric only if has common ratio i.e. $r=\frac{a2}{a1} =\frac{a3}{a2}$ whiere a1,a2 and a3 are first,second and third term of the sequence respectively.

1) Common ratio $r=\frac{-18}{-3}=\frac{-108}{-18}=6\\$

Explicit formula $a_{n} =a_{1} .r^{n-1}$

Now using the above formula, we can find $8^{th} term=-3*(6)^{8-1} =-3*6^{7}=-839808.$

2) Here

$\frac{a2}{a1}\neq \frac{a3}{a2}\\\frac{-2}{-4}\neq \frac{1}{-2}\\\frac{1}{2}\neq\frac{1}{-2}$ so this is not geometric sequence so no need to proceed further.

3) Common ratio $r=\frac{15}{-3}=\frac{-75}{15}=-5\\$

Explicit formula $a_{n} =a_{1} .(-5)^{n-1}$

Now using the above formula, we can find $8^{th} term=-3*(-5)^{8-1} =-3*(-5)^{7}=234375.$

4) Common ratio $r=\frac{-6}{1}=\frac{36}{-6}=-6\\$

Explicit formula $a_{n} =a_{1} .(-6)^{n-1}$

Now using the above formula, we can find $8^{th} term=1*(-6)^{8-1} =1*(-6)^{7}=-279936.$

5)Common ratio $r=\frac{-8}{4}=\frac{16}{-8}=-2\\$

Explicit formula $a_{n} =a_{1} .(-2)^{n-1}$

Now using the above formula, we can find $8^{th} term=4*(-2)^{8-1} =4*(-2)^{7}=-512.$

6)Common ratio $r=\frac{-8}{-2}=\frac{-32}{-8}=4\\$

Explicit formula $a_{n} =a_{1} .(4)^{n-1}$

Now using the above formula, we can find $8^{th} term=-2*(4)^{8-1} =-2*(4)^{7}=-32768.$

3 0

4 years ago

if a motercycle is moving at a constant speed down the highway of 40 km/hr, how long would it the motorcycle to travel 10 km

ahrayia [7]

Answer:

15 minutes

Step-by-step explanation:

First, the motorcycle goes at a speed of 40 km/hr.

The question asks for how long it would take to travel 10 km.

Well, there are 60 minutes in an hour, since we will be translating into minutes.

Also, 10 km is 1/4 of 40 km, so it would make sense that the time length would be 1/4 of an hour as well.

1/4 of 60 minutes is 15 minutes. So it takes 15 minutes for the motorcycle to travel 10 km.

Now, if all this wordy stuff is too much to comprehend, you can also solve using proportional relationships.

$\frac{40km}{60min}=\frac{10km}{xmin}$

Now cross multiply:

$40km*xmin=10km*60min\\40x=600$

Divide both sides by 40:

$\frac{40x}{40}=\frac{600}{40}\\x=15$

Again, this shows that it wouls take 15 minutes for the motorcycle to travel 10 km.

6 0

3 years ago