Rectangle QRST with vertices Q(-6,-1), R(-3,1), S(1,-5), and T(-2,-7)

eduard

This question is about how transformations can affect graphs.

First, we'll want to get rid of that -4 on the function of F.

So we can reflect the function over the y-axis and then compress it by a factor of 4 to make the graph $x^2$ .

Then we can move the graph over to the left 3 because the c value is positive, meaning that we move the graph over to the left.

Finally, we can move the function of by $\frac{2}{3}$ because the d value is positive, meaning that we move the graph up.

Hope this helps.

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6 0

3 years ago

A rectangle has an area of 900square inches. The length of the rectangle is 2.25 times the width.Find the dimensions

Alexeev081 [22]

Answer:

Length = 45 inches and Width = 20 inches

Step-by-step explanation:

Let the width be w.

Length(l)=2.25w

Area = 900 in^2

The formula for the area of a rectangle is Area = length * width

So substituting our values we get:

$A=2.25w*w\\900=2.25w*w\\2.25w^2=900\\w^2=\frac{900}{2.25} \\w^2=400\\w=\sqrt{400} \\w=20$

So we get width = 20 inches

Length = 2.25w

so Length= 2.25*20

=45 inches

3 0

3 years ago

Factor 4x^2+81 over the set of complex numbers.

Hunter-Best [27]

$Use:\\\\i=\sqrt{-1}\to i^2=-1\\\\a^2-b^2=(a-b)(a+b)\\--------------------\\\\4x^2+81=2^2x^2+9^2=(2x)^2-(-9^2)=(2x)^2-(-1)(9^2)\\\\=(2x)^2-(i^2)(9^2)=(2x)^2-(9i)^2=\boxed{(2x-9i)(2x+9i)}$

3 0

4 years ago

Find the slope intercept equation of the line perpendicular to the line 2X-5y=6 and containing the point (2,2)

Romashka [77]

Answer:

The equation of the perpendicular line would be y = -5/2x + 7

Step-by-step explanation:

In order to find this line, we must first find the slope of the original line. We do this by solving for y.

2x - 5y = 6

-5y = -2x + 6

y = 2/5x - 6/5

This shows us a slope of 2/5. TO find the perpendicular slope, we use the opposite and reciprocal. This means we negate 2/5 to get -2/5 and then we flip it to get -5/2. Now that we have this, we can use the slope and the point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 2 = -5/2(x - 2)

y - 2 = -5/2x + 5

y = -5/2x + 7

6 0

3 years ago

point b, o, and y are collinear on by, and bo:oy = 5/8. B is located at (4,2,) o is located at (57/8,-3) and Y is located at (x,

Lena [83]

Given: BO : OY = 5:8. Coordinate B is located at (4,2,) ; O is located at (57/8,-3) and Y is located at (x,y).

We have to determine the coordinate Y.

We will use cross section formula which states:

The coordinates $(x_1,y_1) , (x_2,y_2)$ are divided in the ratio $m_1 : m_2$ by the Coordinate A. So, the coordinates of A are given by the formula: