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Sergio [31]
2 years ago
6

I need help with 1 2 and 3

Mathematics
1 answer:
Yuri [45]2 years ago
3 0
I think the answer was have to be a, B, and C
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Calculate the side lengths a and b to two decimal places.
Zinaida [17]

Answer:

a=10.92 units

b=14.51 units

Step-by-step explanation:

We are given that c=6 units

\angle A=43^{\circ}

\angle B=115^{\circ}

We have to find the side length a and b.

We know that sum of angles of a triangle =180 degrees

\angle A+\angle B+\angle C=180

Substitute the values then we get

43+115+\angle C=180

158+\angle C=180

\angle C=180-158=22^{\circ}

sine law: \frac{a}{sin A}=\frac{b}{sin B}=\frac{c}{sin C}

\frac{a}{sin 43^{\circ}}=\frac{6}{sin 22^{\circ}}

a=\frac{6}{sin 22^{\circ}}\times sin 43^{\circ}

a=10.92 units

\frac{b}{sin 115^{\circ}}=\frac{6}{sin 22^{\circ}}

b=\frac{6}{sin 22^{\circ}}\times sin 115^{\circ}=14.51

b=14.51 units

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3 years ago
1500= 5n- 300 <br> Solve the equation for n . Show work.
quester [9]

Answer: 360 = n

Step-by-step explanation:

1500= 5n - 300

+300        +300

1800=5n

1800/5

360=n

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320/4=8   8 tens /4 tens =2

Step-by-step explanation:

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2 and 8 are alternate exterior angles

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