I need help with 1 2 and 3

Mathematics

1 answer:

Yuri [45]3 years ago

3 0

I think the answer was have to be a, B, and C

You might be interested in

Fiandnd product 3/4 x 1 ,1/2

VMariaS [17]

3/4 times 1 1/2 = 1 1/8

Hope this helps!

7 0

3 years ago

Consider that 620(1.082)x models the average annual health care costs per person, in dollars, as a function of the number of yea

max2010maxim [7]

Answer:

I guess that you want to calculate the difference between the annual healt care costs in 1950 and today.

The equation is:

C(x) = $620*(1.082)^x

in 1950, we have x = 0 (because is the initial year)

then the cost is:

C(0) = $620*1 = $620.

Now, today, in 2020, we have:

x = 2020 - 1950 = 70

then we have:

C(70) = $620*(1.082)^70 = $154,276.7

So, according to this equation, te difference is:

$154,276.7 - $620 = $153,656.6

6 0

3 years ago

If a cot α = 1 and b cos α = 1, find a2 – b 2

S_A_V [24]

The equivalent expression of the different of two square is -1

Given the following expressions

a cot α = 1

a = 1/cot α = sinα/cosα

b = 1/cos α

We are to find the expression a² - b²

According to difference of two squares;

a² - b² = (a + b) (a - b)

Substitute the given expressions into the formula as shown:

$a^2 - b^2 = (\frac{sin \alpha}{cos \alpha} )^2 - (\frac{1}{cos \alpha} )^2\\a^2 - b^2=\frac{sin^2 \alpha}{cos^2 \alpha} -\frac{1}{cos ^2 \alpha}\\a^2 - b^2=\frac{sin^2 \alpha-1}{cos^2\alpha}\\a^2 - b^2=\frac{-(1-sin^2\alpha)}{cos^2\alpha} \\a^2 - b^2=\frac{-os^2 \alpha}{cos^2 \alpha}\\a^2 - b^2 = -1$