Answer:
The system of equations is given as:
x + y = 2.5 .... Equation 1
1.8x + 1.8y = 4.05....Equation 2
Step-by-step explanation:
Kiran says, "I bought 2.5 pounds of red and yellow lentils. Both were $1.80 per pound. I spent a total of $4.05
Let
x represent red lentils
y represent yellow lentils.
x + y = 2.5 .... Equation 1
x = 2.5 - y
$1.80 × x + $1.80 × y = $4.05
1.80x + 1.80y = 4.05....Equation 2
The system of equations is given as:
x + y = 2.5 .... Equation 1
1.8x + 1.8y = 4.05....Equation 2
Answer:
Given, ∠MNP=107 degree.
Therefore, ∠QPN= 107 degree. [as, MN=PQ]
We know, sum of four angles of a quadrilateral is 360 degree.
And as MN=PQ, ∠NMQ=∠MQP.
Therefore, ∠MQP= {360 degree-( 107degree+ 107 degree)}/2
=( 360 degree-214 degree)/2
= 146 degree/2
=73 degree.
hope this will help you.
Step-by-step explanation:
Answer:
about 18.2%
Step-by-step explanation:
All you have to do is divide the result of the percent, so 25.7, by the total, 141.
So 25.7÷141=0.18226950354
We round it to 0.182 and multiply it by 100 to know the percent which is 18.2
Answer:
The angles measured between the shadow and the wall trim and the shadow and the top or bottom of the picture should be equal if the picture is level
Step-by-step explanation:
Whereby the picture is 12 inches above the wall trim and the Sun is casting a shadow on the wall, therefore, the edges of the shadow of a straight edged object is straight
If the picture is level, the shadow cast by the sun is transversal to the wall trim and the line formed by extending the bottom or top of the picture in the direction of the shadow. That is, if the picture is parallel, the shadow cast by the Sun on the wall is transversal to the picture and the wall trim if or when the shadow eventually crosses the picture
With the protractor, the angle between the shadow and the wall trim and the shadow and the top or bottom is measured
The angles measured should be the same if the picture is level.
Answer:
<h3>A Angle 1 and Angle 7 </h3>
Step-by-step explanation:
<h3> I think the Answer is A...</h3>
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