Question

The length of a rectangle is one meter more than 4 times its width. Find the dimensions if the perimeter is 52 meters

Answer 1

$l=4w+1\\ 2l+2w=52\\\\ 2(4w+1)+2w=52\\ 8w+2+2w=52\\ 10w=50\\ w=5\\\\ l=4\cdot5+1\\ l=21$

5 m and 21 m