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Mandarinka [93]
3 years ago
10

Need help ..........​

Mathematics
1 answer:
Scrat [10]3 years ago
5 0
I think this is correct, if not sorry haha-

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Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
2 years ago
The equation y = (-16t – 2)(t-1) represents the height in feet of a beach ball thrown by a child as a function of time, `t`, in
olasank [31]

2 ft

Step-by-step explanation:

The height from which the beach ball was thrown happens when t = 0. So setting t = 0 to get y, we get

y = [-16(0) - 2](0 - 1)

= (-2)(-1)

= 2 ft

Therefore, the ball was thrown from a height of 2 ft.

7 0
3 years ago
What is the quotient to four dived by fifty
allsm [11]
0.08 if 4 divided by 50
12.5 if 50 divided by 4
8 0
3 years ago
Read 2 more answers
2. Miss. Mead pays Miss. Brown $125.00 per week. How much money must Miss. Brown take in for
nadezda [96]

The question is incomplete:

1. A cosmetologist must double his/her salary before the employer con realize any profit from  his/her work,  Miss, Mead paid Miss, Adams $125,00 per week to start.

2. Miss. Mead pays Miss. Brown $125.00 per week. How much money must Miss. Brown take in for  services if Miss. Mead is to realize $50.00 profit on her work? (Conditions on salary are the same  as in problem 1)  

ODS

a. $275.00 b. $325.00 c. $250.00 d. $300.00

Answer:

d. $300.00

Step-by-step explanation:

Given that a cosmetologist must double her salary before the employer can realize any profit from  his/her work, for Miss. Mead to realize $50.00 profit on her work, you would have to determine the amount that doubles the salary of the cosmetologist and add the $50 needed as profit:

Salary= $125*2=$250

$250+$50= $300

According to this, the answer is that for Mead to realize $50.00 profit on her work, Miss. Brown must take $300.

4 0
3 years ago
the population of cities A and B are 3.8 x 10^5 and 2,160,000 , respectively . the population of city C is twice the population
erma4kov [3.2K]
The answer is 4, 320, 000


explanation: the problem is asking what the population of city c is, and to do that you need to multiply city b times 2. therefore you do not need the population of city a, it is just there to confuse you
5 0
3 years ago
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