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Alexxandr [17]
3 years ago
8

You play guitar and keep two files on your computer. One file, called strings, lists the different brands of strings you keep on

hand. Another file, called music, lists the music books and scores you own. When you enter the command paste strings music, what happens
Computers and Technology
1 answer:
Hoochie [10]3 years ago
7 0

Answer is given below

Explanation:

  • when performing in computer and we have two files on the computer first one is string and another one is the music list                
  • so when we enter the command paste strings music than there will they display side by side on the screen.
  • and on the left side of lists the string in screen and the right side is columns list the music book              
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Given six memory partitions of 100 MB, 170 MB, 40 MB, 205 MB, 300 MB, and 185 MB (in order), how would the first-fit, best-fit,
nlexa [21]

Answer:

We have six memory partitions, let label them:

100MB (F1), 170MB (F2), 40MB (F3), 205MB (F4), 300MB (F5) and 185MB (F6).

We also have six processes, let label them:

200MB (P1), 15MB (P2), 185MB (P3), 75MB (P4), 175MB (P5) and 80MB (P6).

Using First-fit

  1. P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
  2. P2 will be allocated to F1. Therefore, F1 will have a remaining space of 85MB from (100 - 15).
  3. P3 will be allocated F5. Therefore, F5 will have a remaining space of 115MB from (300 - 185).
  4. P4 will be allocated to the remaining space of F1. Since F1 has a remaining space of 85MB, if P4 is assigned there, the remaining space of F1 will be 10MB from (85 - 75).
  5. P5 will be allocated to F6. Therefore, F6 will have a remaining space of 10MB from (185 - 175).
  6. P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using First-fit include: F1 having 10MB, F2 having 90MB, F3 having 40MB as it was not use at all, F4 having 5MB, F5 having 115MB and F6 having 10MB.

Using Best-fit

  1. P1 will be allocated to F4. Therefore, F4 will have a remaining space of 5MB from (205 - 200).
  2. P2 will be allocated to F3. Therefore, F3 will have a remaining space of 25MB from (40 - 15).
  3. P3 will be allocated to F6. Therefore, F6 will have no remaining space as it is entirely occupied by P3.
  4. P4 will be allocated to F1. Therefore, F1 will have a remaining space of of 25MB from (100 - 75).
  5. P5 will be allocated to F5. Therefore, F5 will have a remaining space of 125MB from (300 - 175).
  6. P6 will be allocated to the part of the remaining space of F5. Therefore, F5 will have a remaining space of 45MB from (125 - 80).

The remaining free space while using Best-fit include: F1 having 25MB, F2 having 170MB as it was not use at all, F3 having 25MB, F4 having 5MB, F5 having 45MB and F6 having no space remaining.

Using Worst-fit

  1. P1 will be allocated to F5. Therefore, F5 will have a remaining space of 100MB from (300 - 200).
  2. P2 will be allocated to F4. Therefore, F4 will have a remaining space of 190MB from (205 - 15).
  3. P3 will be allocated to part of F4 remaining space. Therefore, F4 will have a remaining space of 5MB from (190 - 185).
  4. P4 will be allocated to F6. Therefore, the remaining space of F6 will be 110MB from (185 - 75).
  5. P5 will not be allocated to any of the available space because none can contain it.
  6. P6 will be allocated to F2. Therefore, F2 will have a remaining space of 90MB from (170 - 80).

The remaining free space while using Worst-fit include: F1 having 100MB, F2 having 90MB, F3 having 40MB, F4 having 5MB, F5 having 100MB and F6 having 110MB.

Explanation:

First-fit allocate process to the very first available memory that can contain the process.

Best-fit allocate process to the memory that exactly contain the process while trying to minimize creation of smaller partition that might lead to wastage.

Worst-fit allocate process to the largest available memory.

From the answer given; best-fit perform well as all process are allocated to memory and it reduces wastage in the form of smaller partition. Worst-fit is indeed the worst as some process could not be assigned to any memory partition.

8 0
3 years ago
The changing of values for an object through a system is represented by the _____. (Points : 6) communication diagram
Fed [463]

Answer:

The correct option is communication diagram

Explanation:

The communication diagram represents the change of values for an item by a system.

A communication diagram is an expansion of the diagram of objects showing the objects together with the texts traveling from one to another. Besides the connections between objects, the communication diagram demonstrates the messages that the objects send to one another.

The correct option is a) communication diagram

8 0
3 years ago
What are the main advantages of the d-step tuning of 2023 murano’s xtronic cvt®?.
DedPeter [7]

The main advantages of the d-step tuning of 2023 Murano's xtronic cvt is that:

  • It gives room for the transmission to quickly change ratios in regards to quick acceleration.
  • When at higher rpm, it help one to stepped acceleration via the use of linear acceleration feel.

<h3>What kind of transmission does a Nissan Murano have?</h3>

It is known to have a continuously variable automatic transmission (CVT) and it is one whose only engine is said to give about a 3.5-liter V-6 that helps to bring about a lot of power.

Note that the main advantages of the d-step tuning of 2023 Murano's xtronic cvt is that:

  • It gives room for the transmission to quickly change ratios in regards to quick acceleration.
  • When at higher rpm, it help one to stepped acceleration via the use of linear acceleration feel.

Learn more about cars from

brainly.com/question/25749514

#SPJ1

6 0
2 years ago
A ____ resembles a circle of computers that communicate with each other.
Sidana [21]

Answer:

ring network

Explanation:

In a ring network, the nodes are arranged in a circular pattern where each node is connected to two adjacent nodes. In this topology, any node can communicate with any other node via the intermediaries.

In comparison,

- in a star network every communication needs to pass through a central hub node

- in a bus, each node is connected to a shared linear communication bus.

- in a hierarchical network nodes are organized along a tree structure layout.

4 0
3 years ago
An organization is planning to implement a VPN. They want to ensure that after a VPN client connects to the VPN server, all traf
Sonja [21]

Answer:

B. Full tunnel.

Explanation:

In this scenario, an organization is planning to implement a virtual private network (VPN). They want to ensure that after a VPN client connects to the VPN server, all traffic from the VPN client is encrypted. The best method to meet this goal is to use a full tunnel.

A full tunnel is a type of virtual private network that routes and encrypts all traffics or request on a particular network. It is a bidirectional form of encrypting all traffics in a network.

On the other hand, a split tunnel is a type of virtual private network that only encrypts traffic from the internet to the VPN client.

Hence, the full tunnel method is the most secured type of virtual private network.

7 0
3 years ago
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