Please help with part b plz
1 answer:
You might be interested in
The sum will be:
sigma(i = 1 to infinity, 30*(2/5)^i)
->
Which is equal to 30/(3/5) = 50
sigma(i = 1 to infinity, 30*(2/5)^i)
->
Which is equal to 30/(3/5) = 50
Solution: Let be the number of adult ticket's.
The number of child ticket
We are given, that an adult ticket cost's $10 and child ticket costs $6. Also the church luncheon made $842.
Therefore,
Therefore, the number of adult ticket's sold = 35
And the number of child ticket's sold = 2 x 35 + 12 = 70 + 12 = 82